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I am trying to figure out how to go about using this Omron MOSFET relay in my project. I will be sending 12V (car voltage) to a radar detector and I want to be able to turn it on/off whenever via the Digital Pin on an Arduino board (max 5V output).

When the digital pin is high it allows 12V to flow to the radar. When the digital pin is low then it shuts out the 12V so no power is going to the radar.

enter image description here

PDF

Do I have the schematic above correct? Am I leaving something out?

Update

Like so:

enter image description here

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2 Answers 2

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Add a resistor in series with the LED, which is inside of the solid state relay (SSR).

More importantly, however, the sketch in the O.P. is a bit backwards sideways. Control signal is between pins 1 & 2. High current path is between pins 3 & 4.

enter image description here

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  • \$\begingroup\$ Would this same setup be suitable with an rca video input (yellow plug) in place of the 12vdc? Would it mess with the signal any when going through it? \$\endgroup\$
    – StealthRT
    Commented Oct 23, 2013 at 4:10
  • \$\begingroup\$ @StealthRT The SSR might limit the bandwidth of the signal. But, I don't know enough about video signal to say for sure. \$\endgroup\$
    – Nick Alexeev
    Commented Oct 23, 2013 at 4:49
  • \$\begingroup\$ For this one clare.com/home/pdfs.nsf/0/D4D22906656FCF5C8525749B004957B8/… i am looking at the DC Load only and am confused... The + Load is on pins 4 and 6 while the - Load is on pin 5. Can you explain to me how i would hook that up using my current 12vdc connection (12v in / 12v out)?? \$\endgroup\$
    – StealthRT
    Commented Oct 23, 2013 at 16:39
  • \$\begingroup\$ see my post about that question above: electronics.stackexchange.com/questions/86318/… \$\endgroup\$
    – StealthRT
    Commented Oct 23, 2013 at 17:54
  • \$\begingroup\$ Does it matter what pin (4 or 3) i use as the "input" and "output"? In your drawing you have pin 3 as output and pin 4 as input. In my drawing i have Pin 3 as input while pin 4 is output.... Which is correct? \$\endgroup\$
    – StealthRT
    Commented Oct 23, 2013 at 22:46
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Pins 1 and 2 are the LED (the "coil" of the relay) and 3 and 4 are the output side (the "contacts").

Pin 1 should go to the Arduino's +5V via a resistor - 390 or 430 ohms would be a suitable value. Pin 2 will go to the Aduino output terminal.

+12 Volts should go to pin 3, and pin 4 to your load.

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