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There are two components 74ABT04D Hex inverter and UCC5304DWVR gate driver. 74ABT04D Hex inverter is the signal genrator UCC5304DWVR is the reciever of the delayed signal. I know that my delay line has to be matched.Given the datasheet below what source and load I need to put for my delay line? THanks. https://www.mouser.co.il/datasheet/2/916/74ABT04-1541721.pdf https://www.ti.com/lit/ds/symlink/ucc5304.pdf?ts=1715329802200&ref_url=https%253A%252F%252Fwww.mouser.co.il%252F

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  • \$\begingroup\$ What delay line are you referring to and where does it go in your circuit? \$\endgroup\$
    – Andy aka
    Commented May 10 at 8:35
  • \$\begingroup\$ Hello Andy the hex invertor creates a square wave pulse , i want to delay it using LC ladder type circuit so it will reach UCC5304DWVR input after some time.However i am not sure what source and load to use by the datasheets of the components when i design this LC ladder in LTSPICE. \$\endgroup\$
    – rocko445
    Commented May 10 at 10:14

1 Answer 1

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A single section of LC delay line needs to be terminated in a resistor of value \$\sqrt{\frac{L}{C}}\$: -

enter image description here

The one above is for 50 Ω i.e. \$\sqrt{\frac{L}{C}}\$ = 50 Ω.

It can also be proven that for a decent range of frequencies (from DC up to a high frequency point), the input impedance will also be \$\sqrt{\frac{L}{C}}\$. The point where it starts to unravel is about one-tenth of the resonant frequency formed by L and C. In the example above, that will be one-tenth of 31.8 MHz.

This means that if you want a decent delay line, you choose the resonant frequency to be about ten times higher than your maximum frequency (including relevant square wave harmonics).

How much delay comes from a single L and C? If I plot the phase response of the output from low frequencies up to (say) 1 MHz I get this: -

enter image description here

In other words, the phase increases linearly with frequency and, this equals a constant time delay. In the example above it 5 ns (\$\sqrt{L\cdot C}\$). At around one tenth of the resonant frequency (around 3.18 MHz) it starts to be a little non-linear in delay so, be aware of what values to pick.

And, of course, the LC section has the same input and output impedance so, multiple sections can be cascaded with a single terminator right at the end of the final section.

Images and some text taken from an answer I gave on Codidact

However I am not sure what source and load to use by the datasheets of the components when I design this LC ladder in LTSPICE.

You have options. Either terminate in a value as per the formula above or use a series terminator in the source of the same value (taking into account that your driving source my be circa 15 Ω. Series source termination example: -

enter image description here

The theoretical delay should be 20 ns but, it's more like 21 ns due to the higher-than-anticipated BW of the signal input (100 ns rise and fall times).

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  • \$\begingroup\$ Hello Andy ,In the datasheet of ucc5304 section 9.1.1 they say not to input delay lines :-) I still want to try.Is there a clue in the datasheet whereis says what in the input impedance of the input to ucc5304? ti.com/lit/ds/symlink/… \$\endgroup\$
    – rocko445
    Commented May 10 at 13:03
  • \$\begingroup\$ It looks like a CMOS input with TTL voltage levels and uses a Schmitt trigger format as per the diagram on page 14 and section 8.3.2. There is no section numbered 9.1.1. \$\endgroup\$
    – Andy aka
    Commented May 10 at 13:17
  • \$\begingroup\$ Hello Andy, from section 8.3.2 shown below and what you said it seems that my load is open circuit (infinite load) but my LC has caracteristic impedance so how can i match the LC section to the "LOAD" in such case? Thanks. ternal pull-down resistor forces the pin low. This resistance is typically 200 kΩ (see Functional Block Diagram). \$\endgroup\$
    – rocko445
    Commented May 10 at 15:04
  • \$\begingroup\$ @rocko445 look at my last paragraph in my answer and try simulating with a source series termination. \$\endgroup\$
    – Andy aka
    Commented May 10 at 16:07
  • \$\begingroup\$ Hello Andy, to tell truth this is the first time i heard of this idia :-) i googled it and saw connecting a transmission line in series I need to use lumped elemented not transmission lines..could you give me an example of series termination which could deal with infinite load(100Kohm) when the pulse could go into the UCC5304 device with no reflections? Thanks \$\endgroup\$
    – rocko445
    Commented May 10 at 16:43

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