Typical PCBs have a dielectric with a low constant \$\varepsilon_r\$. I'm studying the effect the electrical fields on dielectrics and as an experiment would like to test PCBs with a very high dielectric constant, such as using calcium copper titanate with \$\varepsilon_r \approx 10000\$ (the higher \$ \varepsilon_r \$ the better).
This is not for a "practical application" (I understand why typical PCBs don't have a high \$\varepsilon_r\$ and it makes sense - not slow the signal, low signal loss, etc), but this is for an experiment purpose only.
So I would like to know a manufacturer of PCBs that could make such a PCB with a very high (the higher the better) dielectric substrate. As I'm just studying the electric field properties, I only plan to make the traces on one layer (two at the most) and no chips, resistances, capacitors, holes, etc. Just the PCB would be great!
In summary:
- PCB with very high dielectric constant and one layer (two at the most)
- Only traces, no chips/resistances/capacitors/holes/etc
- minimum trace width ~0.25 mm (lower the better)
- minimum trace spacing ~0.25 mm (lower the better)
- Dielectric should support up to 1000 V between traces (I think Calcium copper titanate breaks down at 2 kV/μm so this would work)