I came across a very basic problem in electrical circuits (self studying)
Find v,i and the power of the voltage source in the following electrical circuit.
I am thinking to minimize the circuit after finding all the resistors that are in series and parallel (from right to left) and then apply Ohm's Law $$I =v /R$$.For example 8 and 4 resistors are in series so they make a resistor of 12 ohms.Then this resulted resistor is in parallel with the 6 ohm resistor and so on.Am I correct ?
Procceding in the calculations I end up with a single resistor of 10 ohms because :R1: 2 ohm is in parallel with R2:16 ohm ,in series with R3:12 ohm.R3 is connected in parallel with R4: 6 ohm and in series with R5:4 ohm.
Applying Ohm's Law $$I=\frac{V}{R}=\frac{30V}{10\Omega}=3A$$
To find the voltage across R6, we can use Ohm's law again. Since R6 is in series with R5, we can first calculate the voltage drop across R5:
$$V_{R5} = I * R_5$$ $$V_{R5} = 3 * 4$$ $$V_{R5} = 12 V$$
Next, i calculated the voltage drop across R6 by subtracting the voltage drop across R5 from the total voltage of the circuit:
$$V_{R6} = V_total - V_R5$$ $$V_{R6} = 30 - 12$$ $$V_{R6} = 18 V$$
Therefore, the voltage across R_6 is 18 V. The power is $$p=vi=30*3=90 W$$
