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I have two questions that I would appreciate some help with.

Comparing BPSK and DPSK I noticed that BPSK has lower BER. Why is this? Are there other advantages of using one over the other?

In what specific applications would DPSK be more useful compared to BPSK?

BPSK = Binary Phase Shift Keying

DPSK = Differential Phase Shift Keying

BER = bit error rate

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  • \$\begingroup\$ Would you mind editing your question to provide an expansion of the acronyms you are using? I believe BPSK and DPSK are not mutually exclusive. But maybe you don't mean what I think you mean when you say BPSK and DPSK. Also, please expand BER. The goal is to produce questions and answers which benefit not only you but other people who find the question by searching. Some of those people may not know what phase shift keying or bit error rates are. \$\endgroup\$
    – user57037
    Commented Mar 26, 2021 at 0:30
  • \$\begingroup\$ I assume you mean differential (binary) phase shift keying vs. straight binary phase shift keying. Stackexchange likes clarity in its questions -- could you edit your question to say what you really mean? I don't like starting answers with "assuming that you mean..." \$\endgroup\$
    – TimWescott
    Commented Mar 26, 2021 at 15:26
  • \$\begingroup\$ @TimWescott apologies for any misunderstandings, I have edited the post for the acronyms. \$\endgroup\$
    – fred
    Commented Mar 26, 2021 at 21:57
  • \$\begingroup\$ @mkeith apologies for any misunderstandings, I have edited the post for the acronyms. \$\endgroup\$
    – fred
    Commented Mar 26, 2021 at 21:58

1 Answer 1

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Comparing BPSK and DPSK I noticed that BPSK has lower BER. Why is this?

You can think of DPSK as being a binary data stream that's been run through a differentiator and then encoded with BPSK. I.e., if your original stream is a collection of \$x[k]\$, then your differential stream is a collection of \$x_d[k] = x[k] \oplus x[k-1]\$.

To receive DPSK, you demodulate it like BPSK, then take the first backwards sum (which, because the arithmetic is modulo 2, looks like the first backward difference): for a received stream out of the demodulator of \$\hat x_d\$, you compute \$\hat x[k] = \hat x_d[k] \oplus \hat x_d[k - 1]\$.

This means that a single bit error in your "raw" stream results in two bit errors in your final DPSK stream. So -- higher bit error rate.

Are there other advantages of using one over the other?

Yes. Often when you're sending PSK, you don't have an absolute phase reference. You have to generate your own phase reference from the incoming signal (see carrier recovery). This phase reference just naturally has a 180 degree ambiguity. DPSK takes care of that -- it pays attention to the phase changes, so that phase ambiguity takes care of that.

There have been schemes proposed to do something along the lines of "Well, I'm using forward error correction anyway, so I'll just feed the corrector the true bit stream and an inverted bit stream. Then whichever one has fewer detected errors -- wins!"

The problem with that is that if you have enough noise in your signal that you need forward error correction, you probably have enough noise in your system that it will exhibit a phenomenon where the carrier recovery circuit will slip by 180 degrees when that happens. With plain old DPSK, that would be a single bit error (not even two!). However, with the BPSK -> smart error correction scheme, you get a block of erroneous bits that's up to twice the block size of a block error correction code, or the coherence length of a convolutional code. Since good codes tend to be really long, that means that what would have been just one little error ends up being a whole bunch of useless bits.

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