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i have an input of

$$v_{in} = \sin{(2\pi\cdot f\cdot t)}$$

$$V_{out}=0.5+10\cdot V_{in} +0.1 \cdot V_{in}^3$$

SNDR is the ration between the power of the signal and the power of the noise . in the Vout we will have harmonics of f,3f,DC which of them i consider noise?

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  • \$\begingroup\$ None of them are noise. The ones that aren't there on the input (or at a different relative amplitude or phase on the input) are distortion. \$\endgroup\$
    – user16324
    Commented Sep 28, 2020 at 15:26

1 Answer 1

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SNDR is the ration between the power of the signal and the power of the noise

No, it's the ratio of the signal to the noise-plus-distortion. A very similar term is SINAD i.e. total signal in noise and distortion and, it amounts to largely the same thing.

in the Vout we will have harmonics of f,3f,DC which of them i consider noise?

Well, none of them really. Noise is only really relevant if it's problematic and DC cannot really be regarded as problematic unless your signal is a DC signal. So your output, in the absence of any other information is: -

  • DC (unwanted)
  • f (the wanted signal)
  • 3f (unwanted distortion)
  • noise (zero)
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  • \$\begingroup\$ so SNDR is the power from the cofficient of "f" divided by the power from the coefficients of 3f and power on noise? \$\endgroup\$
    – rocko445
    Commented Sep 28, 2020 at 17:47
  • \$\begingroup\$ Yes, that sounds about right. \$\endgroup\$
    – Andy aka
    Commented Sep 28, 2020 at 17:50

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