Questions tagged [rate-equation]
The rate-equation tag has no usage guidance.
74
questions
2
votes
1
answer
328
views
Finding the rate of a reaction given experimental data for reaction kinetics [closed]
Here is the question:
For the reaction:
$$\ce{2 A + 2 B → C + D}$$
The following data was obtained from three experiments:
\begin{array}{c|ccc}\hline
\bf{Experiment} &\textbf{[A] (mol/L)} &\...
5
votes
2
answers
198
views
Steady-state approach - how to find rate equation for intermediate?
The reaction mechanism for the formation of $\ce{NO2}$ is:
\begin{align}
\ce{NO + NO &<=>[$k_1$][$k_1'$] N2O2} & &\text{ (slow)} \\[0.2cm]
\ce{N2O2 + O2 &->[$k_2$] NO2 +NO2} &...
3
votes
0
answers
86
views
Steady state approximation for three-step cycle
How to write the steady state for $\ce{A}?$
$$\ce{A ->[$k_1$] B ->[$k_2$] C ->[$k_3$] A}$$
Species $\ce{A}$ seems to appear on both side of equation as it uses itself to produce some of ...
4
votes
1
answer
193
views
Can anyone explain, why there are coefficients 2 in the equation for rate of change [A]?
The reaction mechanism for the decomposition of $\ce{A2}$ is thought to be:
\begin{align}
\ce{A2 &<=>[$k_1$][$k_1'$] A + A} & &\text{ (fast)} \\[0.2cm]
\ce{A + B &<=>[$k_2$]...
0
votes
1
answer
2k
views
Does mass affect rate of reaction?
Suppose I am reacting HCl with CuCO3.
Experiment 1: I use 2g powdered CuCO3
Experiment 2: I use 4g powdered CuCO3
All other variables are kept constant.
Will this have any affect on rate of reaction? ...
5
votes
2
answers
5k
views
Determine vmax and enzyme concentration (Michaelis–Menten)
I am given that the enzyme concentration is $\pu{15 nM}$ and the following data:
$$
\begin{array}{rl}
\hline
S/\pu{mM} & V/\pu{mM s^{-1}} \\
\hline
1 & 0.202 \\
2 & 0.368 \\
5 & 0....
3
votes
1
answer
164
views
First or second order reaction
I have that $100$ mM of K$_3$Fe(CN)$_6$ is dissolved in equimolar of the organic ion (which I assume is HCN). In the solution Fe(CN)$_6$$^{3-}$ reacts to form Fe(CN)$_6$$^{4-}$.
The formation of Fe(CN)...
3
votes
1
answer
312
views
Can the RDS be different in different direction in a multi-step reversible reaction?
The following mechanism is given in Peter Sykes when they are "talking about de-esterification" of an ester where the alcohol part is bulky-
Here the second step is given as RDS. According ...
2
votes
0
answers
89
views
Lindemann-HInshelwood mechanism difference between high and low concentration
I have a gas reaction which follows the Lindemann-Hinshelwood mechanism and want to calculate the rate constant at low and at high concentrations of the gas but I find myself stuck at what my next ...
4
votes
0
answers
563
views
Lindemann–Hinshelwood mechanism for a gas reaction
The effective rate constant for a gaseous reaction which proceeds by a Lindemann–Hinshelwood mechanism is $\pu{1.01E-5 s^-1}$ at a concentration of $\pu{4.6E-6 M}$ and $\pu{2.21E-5 s^-1}$ at a ...
2
votes
0
answers
1k
views
Effect of stirring and shaking on chemical kinetics
Why don't we take the effects of stirring and shaking on the rates of chemical reactions? While studying chemical kinetics, I've seen that the rates depend on the concentrations of various species, ...
1
vote
0
answers
123
views
Using the steady state approximation in the decomposition of nitramide to determine rate law
$\ce{O2NNH2 (aq) ->[\mathit{k}_1] O2NNH- (aq) + H+ (aq)}$
$\ce{O2NNH- (aq) + H+ (aq) ->[\mathit{k}_{-1}] O2NNH2 (aq)}$
$\ce{O2NNH- (aq) ->[\mathit{k}_2] N2O(g) + OH- (aq)}$
$\ce{H+ (aq) + OH-...
2
votes
1
answer
104
views
Are the orders of reactants with respect to a reaction different for different starting concentrations?
If the reaction is repeated with $\pu{2 M}$ ethyl iodide the pyridine concentration decreases as shown below. Give the rate law of the reaction in terms of pyridine and ethyl iodide. Explain your ...
8
votes
1
answer
23k
views
What does a fractional order of reaction mean for the mechanism?
I'm doing a high school/sixth form college investigation of the kinetics between magnesium ribbon and hydrochloric acid. I have obtained a rate order was $1.5$ with reference to $[\ce{H+}]$ and hence ...