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-5 votes
1 answer
113 views

Find the pH of a solution obtained by mixing 100 ml 0.1m Na3PO4 and 100 ml 0.1 M NaH2PO4. Given that H3PO4: [Κα₁ = 10^-4, Κα₂ = 10^-7, К��з = 10^-11] [closed]

So, my query is that since NaH2PO4 is a weak acid, and Na3PO4 is a basic salt, wouldn't they react? Another theory was that since NaH2PO4 is a weak acid and Na3PO4 is a salt of strong acid and NaH2PO4,...
qwqwqwerty-7's user avatar
1 vote
0 answers
42 views

Why is it that in a buffer solution the equilibrium concentrations may be assumed to be the initial concentrations? [duplicate]

Considering the Henderson–Hasselbalch equation, $$\text{pH} = \text{p}K_a + \lg \frac{[\ce{AcO⁻}]} {[\ce{AcOH}]}$$ $$\text{p}K_a = \lg \frac{[\ce{AcO⁻}][\ce{H⁺}]} {[\ce{AcOH}]}$$ Why are the values ...
reisan's user avatar
  • 11
0 votes
2 answers
2k views

How to know if a reaction forms H3O+ ions or OH- ions? [closed]

How would you know when an acid or base is paired with $\ce{H2O}$ that it will form an $\ce{OH-}$ ion or a $\ce{H3O+}$ ion? I just started the acid and base equilibrium unit, and I'm just confused on ...
Noaki Sato's user avatar
1 vote
2 answers
393 views

How can I calculate the amount of HF in aquoues solution of NH4F and an aquoues solution of NH4HF2?

Dissociation of $\ce{NH4F}$ and $\ce{NH4HF2}$ in water is complete, I assume: $$\ce{NH4F -> NH4+ + F-}$$ and $$\ce{NH4HF2 -> NH4+ + HF2-}$$ Can I calculate the amount of $\ce{HF}$ in these ...
marietiara's user avatar
-1 votes
1 answer
1k views

Methyl Orange Indicator-Reason for small amount of NaOH [closed]

I used methyl orange as my indicator to titrate a weak acid: At first, I added 3 drops of methyl orange to a solution of the weak acid, $\ce{CH3COOH}$, and the solution turned red. Then, after adding ...
noam Azulay's user avatar
-1 votes
1 answer
3k views

Calculate pH at equivalence point [closed]

Calculate the pH at the equivalence point of a titration of 62 mL of 0.1 M $\ce{CH_3NH_2}$ with 0.20 M HCl. The $\ce{K_b}=4.4\cdot10^{-4}$. At the equivalence point, the moles of CH3NH2 equals the ...
Christopher Marley's user avatar
4 votes
4 answers
4k views

Why does the degree of dissociation change when we dilute a weak acid even though the equilibrium constant is constant?

$K$ represents the ratio of concentrations of molecules in a solution at equilibrium, which means that $Q_\mathrm{r}$ (that ratio at any given point) looks to be identical to $K$. In other words, the ...
Elhamer Yacine's user avatar
-1 votes
2 answers
1k views

Calculate pH of a mixture of a strong base and acid. Knowing only the pH, wt/v%, and volume of both solution. [closed]

Title explains all. I have been stuck on this for an hour and for some reason cannot understand it. I have tried to do an ICE table but get stuck halfway as I do not know whether I would use the w/v ...
Oliver A.'s user avatar
5 votes
1 answer
643 views

Why do my equilibrium calculations on this HF/NH4OH buffer system not match those in literature?

I've been trying to reproduce Figure 2 from this research paper (full text available). The Problem However I can't seem to get the same values as in the paper. I did the math both by hand and with ...
Bob van de Voort's user avatar
3 votes
2 answers
5k views

Why doesn't a buffer solution change ph(Appreciably?)

Consider a buffer solution containing weak acid $\ce{CH3COOH}$ and its salt $\ce{CH3COONa}$: \begin{align} \ce{CH3COOH &<=> CH3COO- + H+} \tag{1}\\ \ce{CH3COONa &-> CH3COO- + Na+} \...
Arishta's user avatar
  • 4,197
1 vote
1 answer
555 views

Acid-Base buffer question

Calculate the change in pH of a buffer made by combining $\pu{500 ml}$ of $\pu{0.1 M}$ $\ce{CH_3CH_2COOH}$ and $\pu{500 ml}$ of $\ce{CH_3CH_2COONa}$, when $0.04$ moles of $\ce{NaOH}$ is added to the ...
John Wahlberg's user avatar
2 votes
2 answers
47k views

Finding new pH after NaOH added to buffer solution

I have a buffer containing 0.2 M of the acid $\ce{HA}$, and 0.15 M of its conjugate base $\ce{A-}$, with a pH of 3.35. I need to find the pH after 0.0015 mol of $\ce{NaOH}$ is added to 0.5 L of the ...
Caesium-133's user avatar
3 votes
1 answer
603 views

Why do acids usually completely react with bases?

When a neutralisation reaction happens, for example, $ \pu{100 mol l^-1}$ of $\ce{HCl}$ with $\pu{100 mol l^-1}$ $\ce{NH_3}$, why does all of the base and acid get converted to salt? Why isn't there ...
Gaurav's user avatar
  • 295