Skip to main content

All Questions

Tagged with
33 votes
4 answers
69k views

Why are solids and liquids not included in the equilibrium constant? What about in a reaction rate calculation?

Take for instance the reaction $$\ce{H2(g) + I2(s) <=> 2HI(g)}$$ The equilibrium constant would not include the solid $\ce{I2}$, but why is this? I have read that its concentration is a ...
1110101001's user avatar
  • 3,256
26 votes
4 answers
4k views

Relation between chemical kinetics and chemical equilibrium

In my chemistry book, the law of chemical equilibrium is derived from the law of mass action: For a reversible chemical reaction $$\ce{aA +bB\rightleftharpoons cC + dD}$$ where $a$, $b$, $c$ and $d$ ...
S R Maiti's user avatar
  • 5,685
21 votes
4 answers
27k views

Why are equilibrium constants unitless?

I haven’t quite reached the point where I can read a full-fledged text on chemical kinetics and thermodynamics yet, so bear with me, please. I’m wondering why a value like $K_\text{eq} = \frac{[\ce{...
readyready15728's user avatar
20 votes
1 answer
619 views

Can a multi-species system oscillate around equilibrium?

In reading about chemical oscillations such as those that occur in the Belousov–Zhabotinsky reaction (BZ), it's often reported that these reactions were initially not taken seriously, because of a ...
N. Virgo's user avatar
  • 1,661
19 votes
2 answers
30k views

Is there a difference between equilibrium and steady state?

The term equilibrium is used in the context of reversible reactions that reach a point where concentrations no longer change. The term steady-state is used in enzyme kinetics when the concentration of ...
Karsten's user avatar
  • 41.2k
15 votes
1 answer
2k views

Can a zeroth order reaction be reversible?

After recently studying about chemical equilibrium, I was convinced that the forward and backward reaction rates meet each other at equilibrium. However thinking about zeroth order reaction annoyed ...
Gamma-1-X-Ray's user avatar
14 votes
2 answers
1k views

What is the molecularity of a reversible reaction?

I know that the definition of molecularity of a reaction is number of species reacting in an elementary step. But considering the theory of microscopic reversibility for elementary reactions, each ...
Udit Gupta's user avatar
13 votes
3 answers
7k views

How is it that the equilibrium constant does not depend on the mechanism?

For a reaction of the form $$\ce{aA + bB <=> cC + dD}$$ the equilibrium constant is $$K_c=\frac{[\ce{C}]^c[\ce{D}]^d}{[\ce{A}]^a[\ce{B}]^b}$$ regardless of the mechanism of the reaction. ...
Greg's user avatar
  • 1,201
9 votes
3 answers
935 views

Why is the equilibrium constant defined that way intuitively?

Suppose we have chemical equation: $$\ce{ aA + bB <=> cC + dD }$$ then equilibrium constant is defined: $$K=\frac{[C]^c[D]^d}{[A]^a[B]^b}$$ but why don't we define it as: $$K=\frac{cd[C][D]...
user153330's user avatar
8 votes
4 answers
833 views

Deriving kinetic equations for reversible reactions

Problem Given the reaction $\ce{A <=>[$k_\mathrm f$][$k_\mathrm b$] B}$ with rate constants $k_\mathrm f = \pu{4E-2 s-1}$ and $k_\mathrm b = \pu{10^{-2} s-1}$. Initially, $\pu{2 mol}$ of $\ce{A}...
TRC's user avatar
  • 1,817
8 votes
3 answers
80k views

Changes in which factors affect both the rate and the rate constant of a first order reaction?

Changes in which factors affect both the rate and the rate constant of a first order reaction? I. temperature II. concentration (A) I only (B) II only (C) Both I and II (D) ...
1110101001's user avatar
  • 3,256
7 votes
2 answers
247 views

first-order binding kinetics with multiple identical binding sites

I have beads in solution at concentration $B$ which have $N$ independent binding sites for a single target molecule at concentration $T$. $T$ is small compared to $B$, so most beads will probably not ...
KBriggs's user avatar
  • 173
7 votes
1 answer
126 views

Arterial blood CO2 content, division and partial pressure

My lecturer cites Boron and Boulpaep's Medical Physiology (2nd edition) for the following claims: the total $\ce{CO2}$ content of arterial blood is $26.4$ mmol/L or $48\%$ v/v (not sure if these ...
James Harrison's user avatar
6 votes
1 answer
635 views

Equilibrium constant for a solid-solid equilibrium

Suppose there are two equations: $$ \begin{align} \ce{A(s) &<=> B(g) + C(s)} &\quad &K_1 \tag{R1}\\ \ce{B(g) &<=> D(s) + E(s)} &\quad &K_2 \tag{R2} \end{align}$$ ...
Aditya Prakash's user avatar
6 votes
1 answer
159 views

Question about relation between two time constants

I am not a chemist, but a neuroscientist, so bear with me. I have struggled with this problem for over a week now and have realized it's a chemical question. I'll try to explain it so no neuroscience ...
Charlee's user avatar
  • 61

15 30 50 per page
1
2 3 4 5
8