All Questions
8
questions
-5
votes
1
answer
45
views
Why should the pH change when I add sodium hydroxide to water? [closed]
I am a student and I am trying to understand the concept of pH.
If I add pure $\ce{NaOH}$ in water, it leads to the formation of $\ce{OH-}$ ions in the water. But this shouldn't lead to any change in ...
0
votes
1
answer
420
views
Find the required water volume to add so that the pH of two solutions will be the same
Question.
We have two flasks: one contains 50 mL of 0.001 M HCl and the other 50 mL of 1M acetic acid.
a) How much water should be added to the more acidic solution so that the pH of the two ...
- 39
1
vote
1
answer
969
views
NaOH + atmospheric CO2: Unexpected results troubleshooting
I've conducted an experiment where a solution of $\pu{4.2 M}$ $\ce{NaOH}$ was left exposed to atmospheric $\ce{CO2}$ for a period of time and titrated using potentiometric titration and potassium ...
- 111
0
votes
0
answers
77
views
Strong Base and weak acid reaction problem
I got the above problem correct by setting up the net ionic equation and finding the limiting reactant. I found that there were 0.01076 moles of NaOH left, and then calculated it's molarity which led ...
- 9
1
vote
2
answers
212
views
Weight of sodium acetate required to get to certain pH
How many grams of $\ce{CH3COONa}$ we need to dissolve in $\pu{2.50 L}$ of water to get a solution with $\mathrm{pH} = 9.00$? Given $K_\mathrm{a}(\ce{CH3COOH}) = 1.75\cdot 10^{-5}$
Like solving a ...
- 305
2
votes
1
answer
2k
views
Mixing Ca(OH)2 with Ca(NO3)2
Mixing $\ce{Ca(OH)_2}$ with $\pu{0.1 M}$ concentration of $\ce{Ca(NO3)2}$.
What will actually happen in the process? What I will see with my eyes? I know that $\ce{Ca^2+}$ cation with concentration ...
- 305
0
votes
1
answer
1k
views
Why is finding [H+] when given [OH-]= 3.57e-5 M wrong when I use -log[OH-]?
Question/Problem
I know that [H+][OH-]=$10^{-14}$
And the problem asks to find out the concentration of H+ when the concentration of OH- is $3.57*10^{-5}$M
By using the equation above i find that ...
- 300
1
vote
1
answer
209
views
Finding pH using the -log, why does my calculation differ from the book's answer?
An aqueous solution containing 0.0020 mol/L barium hydroxide, what is the pH? I do the following: 14-(-log(0.0020))=11.3pH. The answer is 11.6.
2.0*10^-3 mol/L sodium hydroxide solution, what is the ...
