I've bumped into this exercise:
Judging by the mechanism of reaction between D-threose and $\ce{NaBH4}$, do you think the final product will be optically active?
To me looks like a reduction, since $\ce{NaBH4}$ is a lightly reductive agent, but then why the answer is "No, the product is not optically active"?
Is it because of the presence of anomers or there are other reasons?
ce
for chemical equations. For example, typing$$\ce{2KClO3 ->[MnO2] 2KCl + 3O2}$$
will be rendered as: $$\ce{2KClO3 ->[MnO2] 2KCl + 3O2}$$ $\endgroup$