So the problem is this: is the sodium acetate acidic, basic or neutral?
One of my textbooks (ATAR Notes chemistry) says in solution, acetate simply (due to its negative charge) accepts protons and produces hydroxide ions
$$\ce{CH3COO- + H2O <=> CH3COOH + OH-} \tag{1}$$
Hence the [$\ce{OH-}$] increases so solution is basic. Hence acetate is a basic anion.
However, my teacher's notes say:
\begin{align} \ce{CH3COO- + H3O+ &<=> CH3COOH + H2O (l)} \tag{2}\\ \ce{H3O+ + OH- &<=> H2O + H2O} \tag{3} \end{align}
that the acetate ions will be released into solution and thus, to decrease their concentration, some of the $\ce{CH3COO-}$ ions react with $\ce{H3O+}$ (LCP). Consequently, $\ce{H3O+}$ drops and more water ionizes and thus [$\ce{OH-}$] increases (LCP). So the acetate ion is a basic anion.
Which pathway, that leads to the formation of basic solution due to the acetate ion, is the correct one?