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enter image description here I understand the exponential relationship between Ka and temperature, but I had expected it to be curving upwards(because of the $e^x$), and not like a log graph (where y-values increases slower for every increse in x-values). Can someone verify if this graph is legit? This graph is Ka(y-axis) against temperature in Kelvin (x-axis). I have isolated for $K(T_2)$ in the Van't Hoff Equation.

I did an experiment on the Ka values of acetic acid, and when I graphed it out, it was curving upwards like a parabola. Can someone help explain the inconsistencies between the theoretical and experimental data?

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  • $\begingroup$ Your expectations do not consider the differential form of the equation d(ln k)/dT=(Delta H)/(RT^2).dT where the slope explicitly decreases with T due 1/T^2. // Note that due semilogarithmic nature of the chart, the vertical axis is geometrically for ln K, in spite of being for K numerically . $\endgroup$
    – Poutnik
    Commented Jan 1 at 11:05
  • $\begingroup$ But my experiment's graph was also Ka against temperature $\endgroup$
    – Metron
    Commented Jan 1 at 11:07
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    $\begingroup$ Note the 2nd part of my comment. $\endgroup$
    – Poutnik
    Commented Jan 1 at 11:08
  • $\begingroup$ Because I wish to find the theoretical Ka values at different tempeatures, I have rearranged the Van't Hoff equation. $\endgroup$
    – Metron
    Commented Jan 1 at 11:08
  • $\begingroup$ By other words, the chart is exactly as expected. $\endgroup$
    – Poutnik
    Commented Jan 1 at 11:09

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