For example, consider the single-displacement reaction $$\ce{AB + C <=> BC + A}$$ My question is then if writing this reaction as the system \begin{gather} \ce{AB <=> A + B} \\ \ce{B + C <=> CB} \end{gather} is equivalent (surely, adding the reactions up gives the correct stoichiometric coefficients).
The thought behind this question is confusion regarding the notion of a "displacement" reaction. I am confused why in textbooks the displacement reaction is presented as if C is reacting with AB directly; wouldn't C instead be reacting with the free B present in the solution (i.e., the reaction is written more fundamentally as the two reaction system)?
The only time I can think of when this might not be true is if B being bound to A induces some electronic structure change localized on B that makes C able to react with B (and free B is unable to react with C).