In preparation for AP Chemistry this upcoming semester I've been assigned a number of challenge problems. One of them is as following:
Suppose that polluted air has carbon monoxide $(\ce{CO})$ levels of $\pu{15.0 ppm}$. An average human inhales about $\pu{0.50 L}$ of air per breath and takes 20 breaths per minute. If the density of carbon monoxide is $\pu{1.2 g L=1}$, How many milligrams (mg) of carbon monoxide does an average person inhale during an $\pu{8 hour}$ period of time breathing polluted air? (Hint: $\pu{15.0 ppm} \ \ce{CO} = \pu{15.0L} \ \ce{CO}$ per $\pu{1.0E6 L}$ of air.)
I've set up the following stoichiometry to solve this problem:
$$\frac{\pu{8 h}}{1} \times \frac{\pu{60 min}}{\pu{1 h}} \times \frac{\pu{20 breaths}}{\pu{1 min}} \times \frac{\pu{0.50 L} \text{ air}}{\pu{1 breath}} \times \frac{\pu{15.0 L} \ \ce{CO}}{\pu{1.0E6 L} \text{ air}} \times \frac{\pu{1.2 g} \ \ce{CO}}{\pu{1 L} \ \ce{CO}} \times \frac{\pu{1000 mg} \ \ce{CO}}{\pu{1 g} \ \ce{CO}}\\ = \pu{86 mg} \ \ce{CO}$$
My question is regarding the number of significant figures for the solution, which I calculated as $86 g CO
. Initially I assumed two sig-figs were to be used because of the value 1.2 g/L
, but have since noticed that the given duration (8 hours
) only has one sig-fig. So my questions breaks down to: are durations considered in the calculation of sig-figs? If so, would the correct answer be 90 mg CO
as opposed to 86 mg CO
?
TLDR; When calculating sig-figs, do you consider the number of significant-figures for all given values, including durations, or just physical quantities?