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I was wondering if there was anything in the mechanism of a Wacker oxidation that would interfere with ketones or aldehydes already present in the molecule. Ketones and aldehydes can't be oxidized any further under normal circumstances, so I think it should be tolerant of these groups, but I am unsure.

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  • $\begingroup$ Aldehydes can be further oxidised rather readily $\endgroup$
    – Waylander
    Commented Nov 22, 2021 at 7:26

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