I've read that in the preparation of $\ce{H2SO4}$ through the Contact process, on the absortion tower, the gas $\ce{SO3}$ is getting in contact with $\ce{H2SO4} (l)$ , because adding $\ce{SO3}$ to $\ce{H2O}$ is going to cause an exothermic reaction, so:
$\ce{SO3 + H2SO4 -> H2S2O7}$
After this, it is controllable to add water to the oleum in order to produce liquid sulfuric acid.
$\ce{H2S2O7 + H2O → 2 H2SO4}$
But I've seen in other websites that:
$\ce{SO3 + H2O -> H2SO4}$
So I don't know which is the real reaction of the absortion tower, because there are other pages that state that the liquid entering is 98% sulfuric acid, and 2% water, this water reacts with the sulfur trioxide (this little water avoids the heat problem), producing sulfuric acid.
I would like to know which premise is correct.