It is clear that both the hexaamminecobalt(III) ion and the hexakis(trifluoromethyl)cobaltate(III) ion are both low spin (the former is already low spin, and the trifluoromethyl ligand is clearly softer than the ammine ligand) and therefore valence isoelectronic to each other, since the Jahn-Teller effect cannot occur. Since their topological connectivities are the same, they must both be of the "same shape" and therefore be able to form hydrogen bonded networks using the ammine protons and trifluoromethyl fluorides.
Question: Would the solvation properties (dipole moments, hydrogen bonding abilities, and the like) of water sufficient to solubilize the hydrogen-bonded polymer $\ce{[Co(NH3)6][Co(CF3)6]}$? I'm asking this, since the very reason that "$\ce{HF}$ is a weak acid in dilute aqueous solution" is that the $\ce{H3O+}$ and $\ce{F-}$ hydrogen bond is too strong for the $\ce{H3O^+}$ to dissociate and "display its acidity".