0
$\begingroup$

According to what I have studied, the change in Gibb's free energy is only a condition for spontaneity for processes happening at constant pressure and temperature conditions.

Consider a reversible reaction happening in a closed vessel at a constant temperature. We check the feasibility of the reaction at any instant using the following equation:

$\Delta G = \Delta G^{.} + RT\ln(Q) $

As the reaction happens, the partial pressures of each gaseous component will keep on changing as well as the total pressure. Then how can we use Gibb's free energy for checking spontaneity?

Improve this question
$\endgroup$
2
  • $\begingroup$ Why would it be a problem for partial pressures to change? $\endgroup$
    – Raven
    Commented Apr 14, 2020 at 9:00
  • $\begingroup$ What about Helmholtz energy A = U - TS ? $\endgroup$
    – Poutnik
    Commented Apr 14, 2020 at 10:41

1 Answer 1

Reset to default
-1
$\begingroup$

Gibbs energy have an another equation which is:- enter image description here

So according to this equation spontaneity of a reaction depends both on the enthalpy change as well as entropy change. We all know that a system attains stability as the system's energy is lowered that is it has to release energy. If in a reaction energy is released enthalpy change is negative. We also know that a reaction is favoured in the direction of increased chaos or a positive entropy change.

So from this we can see that Enthalpy change is negative and entropy change is positive for a spontaneous reaction to take place and the overall equation of enter image description here

becomes negative that is Gibbs free energy must always be negative for a spontaneous reaction.....Can be applied to any reactions. Hope this helps.

Improve this answer
$\endgroup$

Not the answer you're looking for? Browse other questions tagged or ask your own question.