8 moles of so2 and 4 moles of O2 are mixed in a closed vessel.the reaction proceeds at constant temperature. By the moment when equilibrium sets in,80% of the initial amount of so2 enters into the reaction. The equilibrium pressure would be? My attempt: reaction will be 2so2+O2---->2so3. There will be 1.6mole of so2,0.8 mole of O2 remaining and 6.4 mole of so3 will be formed. Now how to find the equilibrium pressure?
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$\begingroup$ Is 4 bigger than 3.2 ? $\endgroup$– PoutnikCommented Mar 30, 2020 at 5:38
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$\begingroup$ Oh sorry I misread, I have edited. $\endgroup$– SM SheikhCommented Mar 30, 2020 at 5:42
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1$\begingroup$ As the volume is not given you cannot, unless you a priori know the K expressed in equilibrium pressures, as the reaction Quotient is pressure dependent. $\endgroup$– PoutnikCommented Mar 30, 2020 at 5:45
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$\begingroup$ This question given to me had an option 2.17 and an option bearing 'can not be calculated' and clearly answer given to me was 2.17 atm. so I feel it is solvable. $\endgroup$– SM SheikhCommented Mar 30, 2020 at 5:49
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1$\begingroup$ So let have 1 mol of oxygen, at unknown temperature and volume. What is the pressure ? It is as asking for p from p=nRT/V, where you know neither T neither V. $\endgroup$– PoutnikCommented Mar 30, 2020 at 5:53
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