10
$\begingroup$

I've seen a paper by Sikalov [1] that says that $\ce{IH3}$ and $\ce{IH5}$ should be observable. Has anyone actually tried to synthesize such molecules?

References

  1. Sikalov, A. A. Hypervalent Halogen Hydrides $\ce{HalH_n}$ ($\ce{Hal}$ = $\ce{Cl},$ $\ce{Br},$ $\ce{I};$ $n = 3, 5, 7)$: DFT and Ab Initio Stability Prediction. Theor Chem Acc 2019, 139 (1), 8. DOI: 10.1007/s00214-019-2524-0.
Improve this question
$\endgroup$
3
  • $\begingroup$ I've done some literature research but couldn't find anything... $\endgroup$
    – Mr.X
    Commented Dec 13, 2019 at 15:32
  • 4
    $\begingroup$ Under high pressure, maybe? Also is there a reason to put iodine first not hydrogen as in ordinary hydrogen iodide? $\endgroup$
    – Oscar Lanzi
    Commented Dec 13, 2019 at 15:46
  • 4
    $\begingroup$ Oscar Lanzi , in this case, some of Hydrogen atoms are negatively charged. That's probably why the author uses such notation. $\endgroup$
    – Mr.X
    Commented Dec 13, 2019 at 16:29

1 Answer 1

Reset to default
2
+50
$\begingroup$

Not the specific compounds $\ce{IH3}$ and $\ce{IH5}$, but hydrogen-iodine compounds with nonclassical stoichiometriws have been synthesized under high pressure.

Binns et al[1] report two high-pressure, hydrogen-rich hydrogen iodides. The more widely stable one, with empirical formula $\ce{H_{27}I}$ consisting of a hydrogen iodide molecule isolated in a shell of thirteen dihydrogen molecules, is stable from 9 to at least 130 GPa pressure. The second compound, stable up to 12.5 GPa, has two hydrogen iodide molecules per one dihydrogen molecules for an empirical formula $\ce{H2I}$. Both compounds are characterized by synchrotron XRD and Raman spectroscopy, and both have only secondary bonding between the hydrogen iodide component and additional hydrogen rather than hypercoordinated iodine.

Reference

  1. Jack Binns, Philip Dalladay-Simpson, Mengnan Wang, Graeme J. Ackland, Eugene Gregoryanz, and Ross T. Howie (2018)."Formation of H2-rich iodine-hydrogen compounds at high pressure". Phys. Rev. B 97, 024111. https://doi.org/10.1103/PhysRevB.97.024111
Improve this answer
$\endgroup$

Not the answer you're looking for? Browse other questions tagged or ask your own question.