I'm trying to understand the occupied orbital specification in Molpro. They're specified by the OCC flag, while it's stated in the documentation, that
OCC, m1, m2, ..., mn;
where the mᵢ
are the number of occupied orbitals (including core/frozen and closed).
Let's say I want to compute energies in $\ce{N2}$, which has $D_\mathrm{2h}$ symmetry point group, i.e. the following character table: $$D_\mathrm{2h}\\ \begin{array}{ccc} \hline \text{No.} & \text{Name} & \text{Function}\\ 1& \mathrm{A_g} & s \\ 2& \mathrm{B_{3u}} & x \\ 3& \mathrm{B_{2u}} & y \\ 4& \mathrm{B_{1g}} & xy \\ 5& \mathrm{B_{1u}} & z \\ 6& \mathrm{B_{2g}} & xz \\ 7& \mathrm{B_{3g}} & yz \\ 8& \mathrm{A_u} & xyz \\ \hline \end{array} $$
Then, what exactly does the OCC specification in the following code mean?
{hf-scf;
occ,3,1,1,0,2,0,0,0;
wf,14,1,0;
}
In my understanding, it specifies:
- 3 orbitals of $\mathrm{A_g}$ symmetry, i.e. $s$ orbitals
- 1 orbital of $\mathrm{B_{3u}}$ symmetry, i.e. $p_x$ orbital
- 1 orbital of $\mathrm{B_{2u}}$ symmetry, i.e. $p_y$ orbital
- 2 orbitals of $\mathrm{B_{1u}}$ symmetry, i.e. $z$ orbital
What I find strange with this interpretation is the choice of orbitals - why would I choose 3 $s$ orbitals, while only one $p_x$ and 2 $p_z$?