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Jun 13 at 6:00 comment added Poutnik 1/ You have the given [NH3]. 2/ Calculate the equilibrium [OH-]. 3/ Calculate the equilibrium [Cu^2+]. 4/ Calculate the equilibrium [Cu(NH3)4^2+].
Jun 13 at 0:11 comment added Shira I don't quite get the idea. You mean that we should not calculate the equilibrium constant for the dissolution of copper(II) hydroxide by ammonia?
Jun 12 at 19:43 comment added Maurice The equilibrium constant for the formation of copper(II) hydroxide is $\ce{[Cu^{2+}][OH-]^2}$, so it is expressed in $mol^3 L^{-3}$. The equilibrium constant for the formation of tetraamminecopper(II) is $\ce{\frac{[Cu(NH3)4^{2+}]}{[Cu^{2+}][NH3]^4}}$. It is expressed in $mol^{-4}L^{4}$
Jun 12 at 9:53 comment added Shira What do you mean by different unit?
Jun 12 at 8:36 comment added Maurice The equilibrium constant for the formation of copper(II) hydroxide can hardly be compared to the formation of tetraamminecopper(II), because these two constants don't have the same unit.
Jun 12 at 6:37 comment added Poutnik See also Schweitzer reagent and production of "copper silk". In the process, cellulose is dissolved in the ammonia solution of copper(II) hydroxide(dark violet).
Jun 12 at 6:26 comment added Poutnik Have you done the calculation involving the provided constants? // Comparison of constants must consider also different stoichiometries and present concentrations.// CH SE questions are supposed to be self-contained, involving all essential info, with the links serving just as additional reference original text or for further reading. Questing alone should be fully valid even if links stopped working.
Jun 12 at 5:40 history edited andselisk CC BY-SA 4.0
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Jun 11 at 23:33 history asked Shira CC BY-SA 4.0