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andselisk ♦
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In thisAccording to websiteUniversity of Oregon — Chemistry Interactive Demonstrations and Educational Resources — Copper-Ammonia Complex, the equilibrium constant for the formation of copper(II) hydroxide is relatively larger compared to the formation of tetraamminecopper(II). 

This means that Cu(OH)2 is poorly$\ce{Cu(OH)2}$ dissolve in ammonia solution poorly. Yet in fact, it does react really well. So isWhere does this contrastcontradiction come from?

In this website, the equilibrium constant for the formation of copper(II) hydroxide is relatively larger compared to the formation of tetraamminecopper(II). This means that Cu(OH)2 is poorly dissolve in ammonia solution. Yet in fact, it does react really well. So is this contrast?

According to University of Oregon — Chemistry Interactive Demonstrations and Educational Resources — Copper-Ammonia Complex, the equilibrium constant for the formation of copper(II) hydroxide is relatively larger compared to the formation of tetraamminecopper(II). 

This means that $\ce{Cu(OH)2}$ dissolve in ammonia solution poorly. Yet in fact, it does react really well. Where does this contradiction come from?

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Does copper(II) hydroxide dissolve in ammonia solution?

In this website, the equilibrium constant for the formation of copper(II) hydroxide is relatively larger compared to the formation of tetraamminecopper(II). This means that Cu(OH)2 is poorly dissolve in ammonia solution. Yet in fact, it does react really well. So is this contrast?