8
$\begingroup$

Voronoi procedural shading with EEVEE or Cycles

My question relates to Blenders Voronoi or cell fracture feature. How to fracture with a different algorithm? I would like to get polygons fractured with the Chebychev, Manhattan, or Minkowski algorithm. Procedural shading may work for some shading, however I wish to do it polygonal. In the screenshot there is the procedural shading node for it to get some idea what I refer to.

$\endgroup$
2
  • 1
    $\begingroup$ So you don't need fracture it in volume. You want to split plane by procedural texture, right? $\endgroup$
    – vklidu
    Commented Dec 13, 2020 at 18:45
  • $\begingroup$ yes exactly what I would like to do $\endgroup$
    – stm
    Commented Dec 13, 2020 at 20:28

1 Answer 1

11
$\begingroup$

It is not possible natively. And there isn't an easy way ...

You can try create black&white image. I wanted suggest to use newly implemented Trace to GreasePencil, but it didn't work without issues for this kind of image.

enter image description here

So probably would be better to use other app to vectorise (trace) image as Line Art and import as SVG back to Blender, Convert to Mesh, Delete by Limited Dissolve - angle 35°in this case (or dicrease curve resolution to 1 before convert to mesh), Merge by Distance.

enter image description here

Add Plane, select both objects, switch to edit mode and use Knife Project to split plane into parts.

enter image description here


There was a script FractureMe2d with this feature - split plane by image. It was a part of FractureMe file from pildanovak for Blender2.49 that worked at glance. Abandoned.

enter image description here

$\endgroup$
3
  • $\begingroup$ I think this is the solution to get it done. MANY THANKS for your time explaining this. $\endgroup$
    – stm
    Commented Dec 13, 2020 at 22:52
  • $\begingroup$ I gave you credit over at DAZ - again THANKS $\endgroup$
    – stm
    Commented Dec 14, 2020 at 20:04
  • $\begingroup$ I dont know what does it means, but sounds like something good :) So thanks :) $\endgroup$
    – vklidu
    Commented Dec 15, 2020 at 13:17

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .