Return to Answer

The greater than Math node returns 1 (greater than) or 0 (smaller or equal).

You probably want the Maximum option instead of the Greater than:

note that clamping a sine wave will not give you half circles, for that you will need other formula:

$$ \begin{cases} 0 & \texttt{if } M> 2r \\ \sqrt{r^{2}-\left ( M-r \right )^{2}} & \texttt{if } M \leq 2r \end{cases} $$

$$\mathbf{M}=\operatorname{mod}\left(x+r,\ 2r+s\right)\\ \mathbf{r}=\text{radius}\\ \mathbf{s}=\text{spacing}$$

Or since you know the cirlce radius and the spacing between, you can put vertices in optimal positions:

The greater than Math node returns 1 (greater than) or 0 (smaller or equal).

You probably want the Maximum option instead of the Greater than:

note that clamping a sine wave will not give you half circles, for that you will need other formula:

$$ \begin{cases} 0 & \texttt{if } M> 2r \\ \sqrt{r^{2}-\left ( M-r \right )^{2}} & \texttt{if } M \leq 2r \end{cases} $$ $$$$

• $\mathbf{M}=\operatorname{mod}\left(x+r,\ 2r+s\right)$
• $\mathbf{r}=\text{radius}$
• $\mathbf{s}=\text{spacing}$

Or since you know the cirlce radius and the spacing between, you can put vertices in optimal positions:

The greater than Math node returns 1 (greater than) or 0 (smaller or equal).

You probably want the Maximum option instead of the Greater than:

note that clamping a sine wave will not give you half circles, for that you will need other formula:

$$ \begin{cases} 0 & \texttt{if } M< 2r \\ \sqrt{r^{2}-\left ( M-r \right )^{2}} & \texttt{if } M \geq 2r \end{cases} $$

$$\mathbf{M}=\operatorname{mod}\left(x+r,\ 2r+s\right)\\ \mathbf{r}=\text{radius}\\ \mathbf{s}=\text{spacing}$$

Or since you know the cirlce radius and the spacing between, you can put vertices in optimal positions:

The greater than Math node returns 1 (greater than) or 0 (smaller or equal).

You probably want the Maximum option instead of the Greater than:

note that clamping a sine wave will not give you half circles, for that you will need other formula:

$$ \begin{cases} 0 & \texttt{if } M> 2r \\ \sqrt{r^{2}-\left ( M-r \right )^{2}} & \texttt{if } M \leq 2r \end{cases} $$

$$\mathbf{M}=\operatorname{mod}\left(x+r,\ 2r+s\right)\\ \mathbf{r}=\text{radius}\\ \mathbf{s}=\text{spacing}$$

Or since you know the cirlce radius and the spacing between, you can put vertices in optimal positions:

The greater than Math node returns 1 (greater than) or 0 (smaller or equal).

You probably want the Maximum option instead of the Greater than:

note that clamping a sine wave will not give you half circles.

The greater than Math node returns 1 (greater than) or 0 (smaller or equal).

You probably want the Maximum option instead of the Greater than:

note that clamping a sine wave will not give you half circles, for that you will need other formula:

$$ \begin{cases} 0 & \texttt{if } M< 2r \\ \sqrt{r^{2}-\left ( M-r \right )^{2}} & \texttt{if } M \geq 2r \end{cases} $$

$$\mathbf{M}=\operatorname{mod}\left(x+r,\ 2r+s\right)\\ \mathbf{r}=\text{radius}\\ \mathbf{s}=\text{spacing}$$

Or since you know the cirlce radius and the spacing between, you can put vertices in optimal positions: