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$\begingroup$ I must be missing something here. The way I understand your question is that you want pixels to be 40 cm apart. This means that if the camera looks down on, let's say, a soccer field with 105x68 m dimensions, you need the render resolution to be (105/0.4)x(68/0.4) = 262.5x170 pixels. Since the first value isn't an integer, you would need to have 10 cm margin on both (shorter) sides of the field. $\endgroup$– Markus von BroadyCommented Mar 4, 2021 at 22:22
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$\begingroup$ Hello :). Unless you're using Orthographic camera, this will depend more on output resolution, camera distance, focal length and sensor size. Sampling has nothing to do with it. $\endgroup$– jachym michalCommented Mar 4, 2021 at 22:22
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$\begingroup$ @MarkusvonBroady, that does partially answer my question! One detail I forgot to add is this needs to be a 512x512 image, so using your calculations, to calculate out a square soccer field, I would do: length of field = (pixel resolution)*(distance between pixels in m) = 512*0.25 = 128m. Then my last question would be how to make that 128x128m field take the up the entire 512x512 pixels - I'm assuming that's in the camera distance and focal length settings that Jachym Michal mentioned? $\endgroup$– karisCommented Mar 4, 2021 at 23:22
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$\begingroup$ Yes. Camera distance is basically how far away the camera is from an object, making it look smaller. Focal length is a bit trickier to explain, but a high focal length makes things in the camera view look as if they are actually far away but are being zoomed up on with a telescope: more orthographic. $\endgroup$– TheLabCatCommented Mar 5, 2021 at 0:55
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