4
$\begingroup$

I am now reading Galactic Astronomy (1998) by Binney and Merrifield. In this book at p. 44 there is this formula for calculating proper motion vector:

$$\boldsymbol\mu_i = \frac{(\mathbf u_i \times\hat{\mathbf x}_i)\times\hat{\mathbf x}_i}{x_i},$$

where $\mathbf u_i$ is stellar heliocentric velocity, $x_i$ is stellar distance and $\hat{\mathbf x}_i$ is stellar unit position-vector. When using this formula, I found that the proper motion has direction opposite to the stellar velocity (because of two multiplication with position-vector). Wouldn't it be intuitive that the motion has the same direction as the velocity? Did I miss something?

Also, using this illustration:

from Galactic Astronomy (1998) by Binney and Merrifield

component of proper motion vector that is parallel to great circle connecting stellar position-vector $\hat{\mathbf x}_i$ and solar velocity vector $\hat{\mathbf v}_\odot$ could be found by,

$$\mu_{\parallel i} = \frac{\boldsymbol \mu_i \cdot \hat{\mathbf v}_\odot}{\sin{\psi_i}}.$$

I do not see why this is the case. Could someone please give me some hints?

$\endgroup$
1
  • $\begingroup$ @uhoh Great job how you increased the readability of the picture! $\endgroup$
    – B--rian
    Commented Feb 18, 2021 at 8:16

0

You must log in to answer this question.

Browse other questions tagged .