How to log bash command with its output?

Question

I want the actual command line be logged together with its output.

I routinely execute important commands like this:

PERL5LIB=${PERL5LIB}:/something/extra my-command.pl many arguments which I want to save 2>&1 | tee -a my-command.log

Now my-command.log contains both stdout and stderr of my-command.pl. However, it does not contain the actual command line above.

I know of the bash history file; so, I guess, I could copy from there (or from the terminal) by hand, but this is not a good solution, of course.

I guess I could write a shell function which would accept a command line, echo it, and then execute it, but then I would have to deal with the quoting hell.

I tried set -v but that appears to ignore redirection.

script does save the command line (but only if I have start a new shell, not with -c) but it does not work in the emacs shell interaction buffer and it saves the shell prompt too - including the escape sequences! - to its log file, so it is suboptimal.

Answer 1

Try the -x option for bash:

bash -x "PERL5LIB=${PERL5LIB}:/something/extra my-command.pl many arguments which I want to save" 2>&1 | tee -a my-command.log

My test:

$ bash -x -c "echo a bunch of difffernt arguments"
+ echo a bunch of difffernt arguments
a bunch of difffernt arguments