How to copy directory to destination that destination have same link name with source directory's name?

Question

I have a problem. When i copy a folder to destination for that destination has link with source folder name, the link change to directory

$cd /home/srr7
$mkdir jetty_home123 
$ln -s jetty_home123 jetty
$ ls -l
lrwxrwxrwx 1 srr7 srr7   13 Nov 27 14:12 jetty -> jetty_home123
drwxrwxr-x 2 srr7 srr7 4096 Nov 27 14:12 jetty_home123

$cp -rf /opt/jetty /home/srr7

/opt/jetty is directory and contain multiple files.

I want to keep jetty link and copy subfolder and files of /opt/jetty to /home/srr7/jetty/.

How to solve this problem.

Answer 1

I want to keep jetty link and copy subfolder and files of /opt/jetty to /home/srr7/jetty/

Do exactly what you say:

cp -r /opt/jetty/* /home/srr7/jetty/

where /opt/jetty/* resolves to "subfolder(s) and files of /opt/jetty".

Note:

• /opt/jetty/* won't yield hidden directories or files, so they won't be copied.

Possible failure scenarios:

• if /opt/jetty/ contains no non-hidden directories/files at all;
• if /opt/jetty/ contains so many directories/files, so you get argument list too long.