I enjoyed the long conversation behind this interview, which has some great thoughts on the role of the CIO, routes into the tech, how the industry is changing - and why it's always a good idea to ask questions.
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hello linked in fam! , its a wrap up of day 1 and today i solved 2 questions the first one was minimise the maximum array , it was a bit challenging for me.....😶 https://lnkd.in/g2C_SYuk the naive approach is very time consuming and will result in TLE , the better approach would be to use binary search approach over a search space here Second question:- . High-Access Employees https://lnkd.in/gXXpspAX solved this one using brute force approach if you have any better ideas , please drop your ideas in comment section see you tomorrow #6Companies30Days #ReviseWithArsh
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🚀 Day 8 of #75dayDSAchallenge explored tricky linked list problems, where I tried different ways to solve them: 🔍 Problem 1: Cloning a Linked List with Random Pointers To copy a linked list with random pointers, I used these methods: 1. Approach 1: First, I made a copy of the list with only "next" connections. Then, I carefully looked at each node to see how many steps it took to reach the random pointer. After that, I adjusted the links to create the cloned list. 2. Approach 2: I used a handy trick with hashmaps instead of counting steps. I kept track of which original node corresponds to which cloned node, making it easier to set up the random pointers. 3. Approach 3: This was the smartest way! With just one pass through the list and no extra memory, I first cloned the list with only "next" connections. Then, I mixed in the cloned nodes with the original ones. After that, I sorted out the random pointers and separated the two lists again. https://lnkd.in/gVV8AAZk 🔍 Problem 2: Removing Nodes from a Linked List For this problem, I did something different. Instead of scanning the list forwards, I went backward. As I moved backward, I kept track of the maximum value I saw. If a node had a value smaller than the maximum, I removed it. This made the list cleaner and more efficient! https://lnkd.in/g5-w7WY9 🔍 Problem 3: Flattening a Linked List The additional challenge involved flattening a linked list, where each node either points to a child linked list or to the next node in the same level. I navigated through the list, flattening it by rearranging the pointers to form a single-level linked list while preserving the order of elements. https://lnkd.in/gzaEUgqR 📈 Keep following for more adventures in data structures and algorithms! #LinkedLists #DataStructures #Coding #Algorithm #DSA #LinkedInLearning #learninpublic #75dayDSAchallenge #kiit #kiituniversity🧠💻
Remove Nodes From Linked List - LeetCode
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So, you've learned DSA but aren't sure where to practice questions. You can check out https://lnkd.in/dbvxXcbS ; it's the platform you've been looking for. Here's what it offers: • A beginner-friendly Data Structures and Algorithms course. • Interview-related questions. • A roadmap for full-stack development and system design. " Remember, consistency is the key to success ".
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On Day 54 of my #JavaDSA100DaysChallenge, I dedicated time to revising binary search principles, solving key questions, and efficiently managing ongoing semester exams. 📚🎯📝 #100daysofcodechallenge #BinarySearch #SemesterExams #DataStructures #Algorithms >>https://lnkd.in/gznD_zEv
Find Peak Element - LeetCode
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🚀 Day 10 of my #75dayDSAchallenge 🚀 Today was all about conquering three crucial problems in Data Structures and Algorithms! 📊 Here's a glimpse into what I tackled: 1️⃣ Find Peak Element: 🏔️ This problem involves finding a peak element in an array, which is greater than or equal to its neighbors. It's a classic problem that sharpens your understanding of array traversal and optimization techniques. 💡 #PeakElement #ArrayTraversal #DSAChallenge Link: https://lnkd.in/gHhAHyMx 2️⃣ Search in a Sorted Rotated Array:🔍 Imagine having a sorted array that's been rotated at a certain pivot. This problem revolves around efficiently locating a target element within this rotated array. It's a test of your binary search skills under unique circumstances. 🔄 #BinarySearch #RotatedArray #ProblemSolving Link: https://lnkd.in/gndy37-g 3️⃣ Finding Minimum in Sorted Rotated Array: 🔎 Similar to the previous problem, but with a twist! This time, we're hunting for the minimum element in a sorted rotated array. It's an exercise in finding the pivot point and leveraging binary search to nail down the minimum value. 🎯 #MinimumElement #BinarySearch #AlgorithmicThinking Link: https://lnkd.in/gXDsD58m Every problem solved is a step closer to mastery! 💪 Can't wait to tackle what tomorrow brings in this exhilarating journey. Stay tuned for more updates! 🚀 #DSA #Algorithm #ProblemSolving #TechJourney #LinkedInLearning #75dayDSAchallenge #leetcode #coding #kiit #kiituniversity #learninpublic
Find Peak Element - LeetCode
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🚀 Day 13 of my #75DayDSAChallenge complete! 📚 Today was a fruitful journey through algorithmic puzzles, as I successfully cracked three intriguing problems: 1️⃣ "Find the smallest divisor given a threshold": I delved deep into optimizing my algorithm to swiftly identify the smallest divisor that satisfies a given threshold. Implementing various strategies, I honed my skills in efficiency and precision. 💡 Link: https://lnkd.in/g_fDee25 2️⃣ "Check if Grid Satisfies Conditions": This problem immersed me in the intricacies of grid analysis, ensuring that each element adhered to specific conditions. From checking rows and columns to verifying individual cells, I navigated through the grid maze with meticulous attention to detail. 🧩 Link: https://lnkd.in/gtD4x6n3 3️⃣ "Find the Nth root of a number using binary search": Employing the power of binary search, I embarked on a quest to uncover the Nth root of a given number. With each iteration, I refined my binary search technique, inching closer to the elusive solution. 🔍 Link: https://lnkd.in/g8m9hebi Each problem presented its unique set of challenges, pushing the boundaries of my problem-solving prowess. Yet, armed with determination, creativity, and a dash of algorithmic finesse, I emerged victorious. 💪 Tomorrow promises new challenges and opportunities for growth as I continue my journey through the realm of data structures and algorithms. Stay tuned! #DSA #DataStructures #Algorithms #ProblemSolving #leetcode #dsa #kiit #gfg #75daydsachallenge
Find the Smallest Divisor Given a Threshold - LeetCode
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Why You Should Solve DSA Problems Solving data structures and algorithm problems can really augment one's problem-solving acumen over time. If you have solved a fair bit of complex problems, you would have found that there are recurring patterns. As you progressively acquaint yourself with these algorithmic patterns and approaches, it would become easier for you to provide optimised solutions within shorter time intervals. In addition, you can significantly improve your chances of excelling in technical interviews at top companies.
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🅳🅰🆈 4️⃣ #Day4 𝐓𝐨𝐝𝐚𝐲, 𝐥𝐞𝐭'𝐬 𝐞𝐱𝐩𝐥𝐨𝐫𝐞 𝐞𝐟𝐟𝐢𝐜𝐢𝐞𝐧𝐭𝐥𝐲 𝐠𝐞𝐧𝐞𝐫𝐚𝐭𝐢𝐧𝐠 𝐚��𝐥 𝐩𝐨𝐬𝐬𝐢𝐛𝐥𝐞 𝐩𝐞𝐫𝐦𝐮𝐭𝐚𝐭𝐢𝐨𝐧𝐬 𝐨𝐟 𝐚 𝐥𝐢𝐬𝐭! 🔄 𝐏𝐫𝐨𝐛𝐥𝐞𝐦 𝐒𝐜𝐞𝐧𝐚𝐫𝐢𝐨: Suppose we have a list [1, 2, 3], and we want to compute all unique permutations from this set. 𝐒𝐨𝐥𝐮𝐭𝐢𝐨𝐧 𝐀𝐩𝐩𝐫𝐨𝐚𝐜𝐡: 𝟏. Initialize: Begin with an empty solution set. 𝟐. Generate Permutations: Use a backtracking approach to systematically build permutations. 𝟐.𝟏. For the first position, we have 3 choices: either 1, 2, or 3. 𝟐.𝟐. For the second position, select from the remaining options. 𝟐.𝟑. Continue this process until all positions are filled, yielding distinct permutations. 𝟑. Count Permutations: With n = 3, the total number of permutations will be n! (factorial). This method leverages a recursive or iterative strategy to explore all possible combinations efficiently. 💡 𝐒𝐡𝐚𝐫𝐞 𝐘𝐨𝐮𝐫 𝐈𝐧𝐬𝐢𝐠𝐡𝐭𝐬: Have you encountered similar problems or have alternative approaches to share? Let's discuss! 💬💻 𝐂𝐡𝐚𝐥𝐥𝐞𝐧𝐠𝐞 𝐋𝐢𝐧𝐤: https://lnkd.in/de6n7pB3 #DataStructures #SoftwareDevelopment #CodingChallenge #TechCommunity #DSA #Algorithms #ProblemSolving Note: This problem has been posed by Google multiple times, adding to its significance! 🌟 Feel free to connect and share your insights! 🚀
Permutations - LeetCode
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Day 12: 30 Days DSA Challenge 🚀 Problem 1: Remove Nodes From Linked List 🔗 Problem Statement: Given a linked list, remove all nodes that have a value greater than a subsequent node. Return the head of the modified linked list. Approach: To solve this problem, we need to traverse the linked list and compare each node with its next node. If the current node's value is greater than the next node's value, we remove the current node. A two-pass approach (traversing the list twice) can ensure that all required nodes are removed. Reverse the Linked List: 🔄 By reversing the list, we can easily compare each node with its next node in a single traversal. Remove Nodes: ✂ Traverse the reversed list and keep track of the maximum value seen so far. If the next node's value is less than the maximum, we remove it. Reverse Again: 🔄 Finally, reverse the list again to restore the original order, minus the removed nodes. Problem 2: Power of Two 🔢 Problem Statement: Given an integer n, return true if it is a power of two. Otherwise, return false. Approach: A number n is a power of two if there exists an integer x such that n == 2^x. There are several ways to determine if a number is a power of two: Iterative Division: Continuously divide the number by 2. If we reach 1 and all divisions are exact (no remainders), the number is a power of two. Bit Manipulation: A power of two has exactly one bit set in its binary representation. Thus, n should satisfy the condition n > 0 and n & (n - 1) == 0. These two problems demonstrate essential skills in linked list manipulation and bitwise operations, critical for mastering data structures and algorithms. Continue practicing daily to sharpen your problem-solving abilities! 🌟💪
Power of Two - LeetCode
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Interesting read.
How many jobs are available in technology in the US?
https://www.computerworld.com
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