From Hawking radiation? No.
The Hawking radiation emitted is inversely proportional to the black hole's size. To make the black hole glow with enough light to be as bright as a star from Hawking radiation alone, it would need to be very small.
The problem with very small black holes is they also have very short lifetimes due to the Hawking radiation robbing them of energy, and thus mass ($E=mc^2$ after all). These small black holes eventually have a runaway of Hawking radiation and explode. This is the ultimate fate of all black holes in our universe, but on very large time scales.
As other answers have mentioned, a black hole that can emit photons in the optical EM range will have a mass of a small fraction of the Moon (~1%), and live for a very long time (~$10^{40}$ years). However, in order to emit such relatively high energy photons for such a long time, a black hole this size must burn VERY, VERY slowly. The SI unit for delivery of energy is the watt, and is roughly the same watt as a common household lightbulb.
1% of lunar mass is around 7e20 kg, and this would have an emitted power of ~7.3e-10 watts. Such a black hole would still be far too weak to warm any planets in orbit. The received flux of the planet Earth is, for reference, is around 1000 watts/m2, and this is an infinitesimal fraction of the Sun's total power output of 3.8e26 watts. This measure is called irradiance, and essentially tells you how many photons are passing through any given area at any given time.
If we assume the black hole is emitting photons at 700nm (a reddish color that is good for photosynthesis) at this wattage, it will emit 2.3 billion photons per second (per the Planck-Einstein relation and the definition of the watt as a joule-per-second). This may sound like a lot, but a 100 watt incandescent lightbulb is emitting $10^{32}$ photons per second, so your black hole is going to be extremely dim.
Irradiance is subject to the inverse-square law, so as you move away from the source, the received energy drops by the square of the distance. If your starting power is 1, and you double the distance, you now get 1/2 the power, triple the distance you get 1/9 the power, etc... Since your black hole is already only emitting less than a nanowatt, it only gets worse from there. Even if your black hole sits on the surface of your planet, it won't be able to warm the surrounding area, much less the entire planet.
However, it is possible for a planet in a black hole system to be illuminated, but only if there is a source of gas. Gas falling into a black hole can form an accretion disk, where the speed of the orbiting gas can release radiation through Bremsstrahlung and friction. This is why, for example, we were able to take the picture of M87*. What we were imaging was not the black hole itself, nor its Hawking radiation, but the light off of its accretion disk.
Unfortunately, the accretion disk needs to be replenished, so you will need a source of gas for it. In addition, the presence of this source of gas is likely to make orbits around your black hole unstable, which is not good news for your planet.
However, it is not impossible from a scientific standpoint, just less probable, and rather unlikely, that your planet will stay in a stable position long enough for life to evolve into anything interesting.
Keep in mind as well, that most black holes form as a result of supernovae, meaning that any planets around the star that explodes will be sterilized and probably vaporized by the creation of the black hole in the first place.