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    $\begingroup$ to clarify: by 2/3 atm you mean 2 or 3 atmospheres, not 0.666 atmospheres? $\endgroup$ Commented Jun 26 at 16:41
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    $\begingroup$ Yes, hold on let me clarify that $\endgroup$ Commented Jun 26 at 16:41
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    $\begingroup$ But even on your graph a pressure of 3 atm yields an equator with an average temperature of ~305K (32°C/90°F) and poles with an average temperature of 265K (-8°C/18°F). It's not as substantial a spread as Earth, but it's still very much tropical/desert equator vs tundra poles. 10 bar gives temperate poles with an average annual temperature comparable to Scandanavia, central Asia, or southern Canada/northern US. It's not until the 100 bar graph that the poles come up to sub-tropical temperatures, comparable to Florida or most of Australia. $\endgroup$ Commented Jun 27 at 6:11
  • $\begingroup$ Thanks for this informative answer! $\endgroup$
    – cconsta1
    Commented Jun 27 at 9:36
  • $\begingroup$ I suppose you could (theoretically) be in a trinary system where you have suns in just the right positions to warm the poles and the equator equally. But I suspect the probability of finding the perfect orbit(s) to maintain that would be miniscule, if it's possible at all. $\endgroup$
    – The Betpet
    Commented Jun 27 at 13:56