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value of $VAR already contains backtick and/or single quote inside. How to handle it? How to properly pass $VAR to program? [duplicate]
$ bash --version
GNU bash, versione 5.2.26(1)-release (x86_64-pc-linux-gnu)
I don't know how to deal with $VAR when its value inside contains single quote (') and/or backtick (`).
I'm in the need of ...
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