Skip to main content

You are not logged in. Your edit will be placed in a queue until it is peer reviewed.

We welcome edits that make the post easier to understand and more valuable for readers. Because community members review edits, please try to make the post substantially better than how you found it, for example, by fixing grammar or adding additional resources and hyperlinks.

7
  • Sounds like "charge/discharge rate" is less than what the power supply actually outputs when the laptop is running.
    – Bergi
    Commented Nov 28, 2021 at 22:49
  • 2
    @Suncatcher: Voltage here is batter voltage, not USB-C voltage. I don't expect the USB-C PD voltage to be the same; the laptop will almost certainly have an internal voltage regulator and battery charger that converts from the PD voltage over the wire to a charge current for the battery. (Typically by regulating for a specific charge current, whatever voltage is necessary to achieve that. But USB-C PD works by asking for a voltage, so you definitely can't just connect that across battery terminals without risking a fire from a high current in or out of the battery.) Commented Nov 29, 2021 at 5:11
  • 2
    Is the point of this answer to look at the battery charge rate and assume the laptop is pulling the max 3A at some voltage, then solve for voltage? (After assuming the laptop is drawing some watts itself, so CPU/screen power + charge rate = V * I, where I = 3 amps? Commented Nov 29, 2021 at 5:13
  • 1
    These are the right measurements at the wrong part of the circuit.
    – Ben Voigt
    Commented Nov 29, 2021 at 22:06
  • CPU/screen power + charge rate = V * I so without knowing CPU/screen power we are out of the luck?
    – Suncatcher
    Commented Nov 30, 2021 at 9:46