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  • You could probably use =(VLOOKUP($C10,Trans_CIQ!$A$8:$AZ$95,Trans_CIQ!$A$886,0)*100000)
    – PeterH
    Commented Jul 27, 2018 at 14:08
  • @PeterH not and maintain the functionality of the formula. INDEX(Trans_CIQ!$A$886:$AZ$886,1,0) is actually return a 1 dimensional array of 52 values, to the match to search. Commented Jul 27, 2018 at 14:16
  • @Scott where it indexes as Row 1 & Column 0, will that not always be the same Cell $A$886 ?
    – PeterH
    Commented Jul 27, 2018 at 14:21
  • Yup skipped right over the second criterion. It should just get rid of the INDEX PART but leave the rest of the MATCH replacing the INDEX with either -1,0,1 @PeterH Commented Jul 27, 2018 at 14:23
  • And no when using 0 in INDEX it returns the whole row or column @PeterH Commented Jul 27, 2018 at 14:24