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0 votes
1 answer
153 views

Dependence through an unknown parameter?

Consider an urn from which we sample with replacement. Let $\pi$ represent the proportion of the urn's balls that are black, with the remainder being white. From a frequentist perspective, each ...
Trisoloriansunscreen's user avatar
0 votes
0 answers
9 views

Bayesian network extracting further conditional independence statements then just from d-separation theorem

Given a Bayesian network $(p,\mathcal{G})$, where $p$ is our joint distribution, and $\mathcal{G}$ is a DAG. Then by the d-separation theorem we can deduce conditional independence statements, in ...
Dylan Dijk's user avatar
0 votes
0 answers
31 views

Bayes Rule with conditional independence of two tests based on a common blood sample

I have the following scenario of Bayes updating with which I struggle quite a bit. Imagine we are interested in the probability that a given person has a disease $D$. We perform two different tests $...
user394691's user avatar
1 vote
1 answer
86 views

How to show mathematically whether the following conditional relationships hold?

In the following Bayesian network, the variables $ x_{i} $ are mutually independent (let's assume that these are the positions of $N$ boats). The variables $ y_{i,j} $ are distance measurements ...
Gouz's user avatar
  • 204
6 votes
1 answer
663 views

Are two coin flips conditionally independent if we know that the coin is biased towards heads?

Suppose Alice (A) and Bob (B) each flip the same, potentially-biased coin. Then, P(A=H) < P(A=H | B=H), because Bob's flip increases our suspicion that the coin is biased towards heads. Now ...
monk's user avatar
  • 475
0 votes
0 answers
833 views

Naive bayes example by hand

Given the following data ...
baxx's user avatar
  • 946
1 vote
1 answer
187 views

Assuming n variables are conditionally independent given y, how do I compute p(y | x_1,...,x_n)?

Referencing this question, I know that if $x_1$ and $x_2$ are conditionally independent given $y$ (big assumption), then $$P(y | x_1,x_2) = \frac{P(x_1,x_2 | y)P(y)}{P(x_2 | x_1)P(x_1)}$$ $$ = \frac{...
D. Rad's user avatar
  • 11