How do I test if a variable is a number in Bash?

Question

I just can't figure out how do I make sure an argument passed to my script is a number or not.

All I want to do is something like this:

test *isnumber* $1 && VAR=$1 || echo "need a number"

Any help?

Answer 1

One approach is to use a regular expression, like so:

re='^[0-9]+$'
if ! [[ $yournumber =~ $re ]] ; then
   echo "error: Not a number" >&2; exit 1
fi

If the value is not necessarily an integer, consider amending the regex appropriately; for instance:

^[0-9]+([.][0-9]+)?$

...or, to handle numbers with a sign:

^[+-]?[0-9]+([.][0-9]+)?$

Answer 2

Without bashisms (works even in the System V sh),

case $string in
    ''|*[!0-9]*) echo bad ;;
    *) echo good ;;
esac

This rejects empty strings and strings containing non-digits, accepting everything else.

Negative or floating-point numbers need some additional work. An idea is to exclude - / . in the first "bad" pattern and add more "bad" patterns containing the inappropriate uses of them (?*-* / *.*.*)

Answer 3

The following solution can also be used in basic shells such as Bourne without the need for regular expressions. Basically any numeric value evaluation operations using non-numbers will result in an error which will be implicitly considered as false in shell:

"$var" -eq "$var"

as in:

#!/bin/bash

var=a

if [ -n "$var" ] && [ "$var" -eq "$var" ] 2>/dev/null; then
  echo number
else
  echo not a number
fi

You can can also test for $? the return code of the operation which is more explicit:

[ -n "$var" ] && [ "$var" -eq "$var" ] 2>/dev/null
if [ $? -ne 0 ]; then
   echo $var is not number
fi

Redirection of standard error is there to hide the "integer expression expected" message that bash prints out in case we do not have a number.

CAVEATS (thanks to the comments below):

• Numbers with decimal points are not identified as valid "numbers"
• Using [[ ]] instead of [ ] will always evaluate to true
• Most non-Bash shells will always evaluate this expression as true
• The behavior in Bash is undocumented and may therefore change without warning
• If the value includes spaces after the number (e.g. "1 a") produces error, like bash: [[: 1 a: syntax error in expression (error token is "a")
• If the value is the same as var-name (e.g. i="i"), produces error, like bash: [[: i: expression recursion level exceeded (error token is "i")

Answer 4

Nobody suggested bash's extended pattern matching:

[[ $1 == ?(-)+([0-9]) ]] && echo "$1 is an integer"

or using a POSIX character class:

[[ $1 == ?(-)+([[:digit:]]) ]] && echo "$1 is an integer"

Answer 5

Some performance and compatibility hints

There are some strongly different methods regarding different kinds of tests.

I reviewed most relevant methods and built this comparison. Mostly:

• Charles Duffy's answer, based on bash regex,
• jilles's answer based on case switches,
• glenn jackman's answer based on bash parameter expansion and
• Alberto Zaccagni's answer based of integer capabilities.

Unsigned Integer is_uint()

These functions assess whether an expression is an unsigned integer, i.e. consists entirely of digits.

• Using parameter expansion

  (glenn jackman's answer based on bash parameter expansion. This was my approach before all this!)

  isuint_Parm() { [ "$1" ] && [ -z "${1//[0-9]}" ] ;}
  

• Using fork to grep

  Proposed by Sergio Abreu's answer

  isuint_Grep() { grep -qE '^[0-9]+$' <<<"$1"; }
  

  I test this method only once because it's very slow. This is just there to show what not to do.

• Using bash integer capabilities

  isuint_Bash() { (( 10#$1 >= 0 )) 2>/dev/null ;}
  

  or even:

  isuint_Bash() { set -- "${1//[+-]/.}";(( 10#$1 >= 0 )) 2>/dev/null ;}
  

  But don't use this!!! Thanks to gniourf_gniourf's comment for driving me to this!

• Using case

  jilles's answer based on case switches

  isuint_Case() { case $1 in ''|*[!0-9]*) return 1;;esac;}
  

• Using bash's regex

  Charles Duffy's answer, based on Bash regex

  isuint_Regx() { [[ $1 =~ ^[0-9]+$ ]] ;}
  

Signed integer is_int()

These functions assess whether an expression is a signed integer, i.e. as above but permitting an optional sign before the number.

• Using parameter expansion

  isint_Parm() { local chk=${1#[+-]}; [ "$chk" ] && [ -z "${chk//[0-9]}" ] ;}
  

• Using bash integer capabilities

  Something like Alberto Zaccagni's answer based on integer:

  isint_Shell() {  [ -n "$1" ] && [ "$1" -eq "$1" ] 2>/dev/null;}
  

  Or using bashisms:

  isint_Bash() {  set -- "${1//[!+-]}" ${1#${1//[!+-]}};
                  (( ( 0 ${1:-+} 10#$2 ) ? 1:1 )) 2>/dev/null ;}
  

• Using case

  isint_Case() { case ${1#[-+]} in ''|*[!0-9]*) return 1;;esac;}
  

• Using bash's regex

  isint_Regx() { [[ $1 =~ ^[+-]?[0-9]+$ ]] ;}
  

Number (unsigned float) is_num()

These functions assess whether an expression is a floating-point number, i.e. as above but permitting an optional decimal point and additional digits after it. This does not attempt to cover numeric expressions in scientific notation (e.g. 1.0234E-12).

• Using parameter expansion

  isnum_Parm() { local ck=${1#[+-]};ck=${ck/.};[ "$ck" ]&&[ -z "${ck//[0-9]}" ];}
  

• Using bash's regex

  isnum_Regx() { [[ $1 =~ ^[+-]?([0-9]+([.][0-9]*)?|\.[0-9]+)$ ]] ;}
  

• Using case

  isnum_Case() { case ${1#[-+]} in ''|.|*[!0-9.]*|*.*.*) return 1;; esac ;}
  

Tests of concepts

(You could copy/paste this test code after the previously declared functions.)

testcases=(
    0  1 42 -3 +42 +3. .9 3.14 +3.141 -31.4 '' . 3-3 3.1.4 3a a3 blah 'Good day!'
);printf '%-12s %4s %4s %4s %4s %4s %4s %4s %4s %4s %4s %4s %4s %4s\n' \
    Value\\Func U{Prm,Grp,Bsh,Cse,Rgx} I{Prm,Shl,Bsh,Cse,Rgx} N{Prm,Cse,Rgx};\
for var in "${testcases[@]}";do
    outstr='';
    for func in isuint_{Parm,Grep,Bash,Case,Regx} \
          isint_{Parm,Shell,Bash,Case,Regx} isnum_{Parm,Case,Regx};do
        if $func "$var"; then
            outstr+='   ##'
        else
            outstr+='   --'
        fi
    done
    printf '%-11s %s\n' "$var" "$outstr"
done

Should output:

Value\Func   UPrm UGrp UBsh UCse URgx IPrm IShl IBsh ICse IRgx NPrm NCse NRgx
0              ##   ##   ##   ##   ##   ##   ##   ##   ##   ##   ##   ##   ##
1              ##   ##   ##   ##   ##   ##   ##   ##   ##   ##   ##   ##   ##
42             ##   ##   ##   ##   ##   ##   ##   ##   ##   ##   ##   ##   ##
-3             --   --   --   --   --   ##   ##   ##   ##   ##   ##   ##   ##
+42            --   --   --   --   --   ##   ##   ##   ##   ##   ##   ##   ##
+3.            --   --   --   --   --   --   --   --   --   --   ##   ##   ##
.9             --   --   --   --   --   --   --   --   --   --   ##   ##   ##
3.14           --   --   --   --   --   --   --   --   --   --   ##   ##   ##
+3.141         --   --   --   --   --   --   --   --   --   --   ##   ##   ##
-31.4          --   --   --   --   --   --   --   --   --   --   ##   ##   ##
               --   --   --   --   --   --   --   --   --   --   --   --   --
.              --   --   --   --   --   --   --   --   --   --   --   --   --
3-3            --   --   --   --   --   --   --   ##   --   --   --   --   --
3.1.4          --   --   --   --   --   --   --   --   --   --   --   --   --
3a             --   --   --   --   --   --   --   --   --   --   --   --   --
a3             --   --   --   --   --   --   --   --   --   --   --   --   --
blah           --   --   --   --   --   --   --   --   --   --   --   --   --
Good day!      --   --   --   --   --   --   --   --   --   --   --   --   --

I hope!

Note: uint_bash seems not perfect! In detail: gniourf_gniourf's second comment rightly said:

All methods using arithmetic context are subject to arbitrary code injection and are very dangerous! All the *_Bash functions here are dangerous and should be marked as ANTI=PATTERNS and "DANGEROUS: SUBJECT TO ARBITRARY CODE INJECTION. SHOULD NOT BE USED UNDER ANY CIRCUMSTANCES".

Performance comparison

Then I've built this test function:

testFunc() {
    local tests=1000 start=${EPOCHREALTIME//.}
    for ((;tests--;)) ;do
        "$1" "$3"
    done
    printf -v "$2" %u $((${EPOCHREALTIME//.}-start))
}
percent(){ local p=00$((${1}00000/$2));printf -v "$3" %.2f%% ${p::-3}.${p: -3};}
sortedTests() {
    local func NaNTime NumTime ftyp="$1" nTest="$2" tTest="$3" min i pct line
    local -a order=()
    shift 3
    for func ;do
        testFunc "${ftyp}_$func" NaNTime "$tTest"
        testFunc "${ftyp}_$func" NumTime "$nTest"
        order[NaNTime+NumTime]=${ftyp}_$func\ $NumTime\ $NaNTime
    done
    printf '%-12s %11s %11s %14s\n' Function Number NaN Total
    min="${!order[*]}" min=${min%% *}
    for i in "${!order[@]}";do
        read -ra line <<<"${order[i]}"
        percent "$i" "$min" pct
        printf '%-12s %9d\U00B5s %9d\U00B5s  %12d\U00B5s  %9s\n' \
               "${line[@]}" "$i" "$pct"
    done
}

I could run in this way:

sortedTests isuint "This is not a number." 31415926535897932384 \
            Case Grep Parm Bash Regx ;\
sortedTests isint  "This is not a number." 31415926535897932384 \
            Case Parm Shell Bash Regx ;\
sortedTests isnum "This string is clearly not a number..." \
            3.141592653589793238462643383279502884  Case Parm Regx

On my host, this shows somthing like:

Function          Number         NaN          Total
isuint_Case       1763µs      1535µs          3298µs    100.00%
isuint_Parm       2571µs      3319µs          5890µs    178.59%
isuint_Regx       5014µs      5952µs         10966µs    332.50%
isuint_Bash       6379µs      6106µs         12485µs    378.56%
isuint_Grep     293347µs    287733µs        581080µs  17619.16%

Function          Number         NaN          Total
isint_Case        2020µs      1938µs          3958µs    100.00%
isint_Parm        3291µs      4707µs          7998µs    202.07%
isint_Shell       5775µs      5183µs         10958µs    276.86%
isint_Regx        5371µs      5836µs         11207µs    283.15%
isint_Bash        8946µs      7718µs         16664µs    421.02%

Function          Number         NaN          Total
isnum_Case        2181µs      2232µs          4413µs    100.00%
isnum_Parm        4502µs      6017µs         10519µs    238.36%
isnum_Regx        8247µs     13019µs         21266µs    481.89%

You could download the full isnum comparison script here or the full isnum comparison script as text here (with UTF8 and LATIN handling).

Conclusion

• The case way is clearly the quickest! About 3x quicker than regex and 2x quicker than using parameter expansion.
• forks (to grep or any binaries) should be avoided when not needed, mostly for small strings, a single line, or other one shot operations.

The case method has become my favored choice:

is_uint() { case $1        in '' | *[!0-9]*              ) return 1;; esac ;}
is_int()  { case ${1#[-+]} in '' | *[!0-9]*              ) return 1;; esac ;}
is_unum() { case $1        in '' | . | *[!0-9.]* | *.*.* ) return 1;; esac ;}
is_num()  { case ${1#[-+]} in '' | . | *[!0-9.]* | *.*.* ) return 1;; esac ;}

About compatibility

For this, I wrote a little test script based on previous tests, with:

for shell in bash dash 'busybox sh' ksh zsh "$@";do
    printf "%-12s  " "${shell%% *}"
    $shell < <(testScript) 2>&1 | xargs
done

This shows:

bash          Success
dash          Success
busybox       Success
ksh           Success
zsh           Success

As I know other bash based solution like regex and bash's integer won't work in many other shells and forks are resource expensive, I would prefer the case way (just before parameter expansion which is mostly compatible too).

Answer 6

This tests if a number is a non-negative integer. It is shell independent (i.e. without bashisms) and uses only shell built-ins:

[ ! -z "${num##*[!0-9]*}" ] && echo "is a number" || echo "is not a number";

---

A previous version of this answer proposed:

[ -z "${num##[0-9]*}" ] && echo "is a number" || echo "is not a number";

but this is INCORRECT since it accepts any string starting with a digit, as jilles suggested.

Answer 7

I'm surprised at the solutions directly parsing number formats in shell. shell is not well suited to this, being a DSL for controlling files and processes. There are ample number parsers a little lower down, for example:

isdecimal() {
  # filter octal/hex/ord()
  num=$(printf '%s' "$1" | sed "s/^0*\([1-9]\)/\1/; s/'/^/")

  test "$num" && printf '%f' "$num" >/dev/null 2>&1
}

Change '%f' to whatever particular format you require.

Answer 8

I was looking at the answers and... realized that nobody thought about FLOAT numbers (with dot)!

Using grep is great too.
-E means extended regexp
-q means quiet (doesn't echo)
-qE is the combination of both.

To test directly in the command line:

$ echo "32" | grep -E ^\-?[0-9]?\.?[0-9]+$  
# answer is: 32

$ echo "3a2" | grep -E ^\-?[0-9]?\.?[0-9]+$  
# answer is empty (false)

$ echo ".5" | grep -E ^\-?[0-9]?\.?[0-9]+$  
# answer .5

$ echo "3.2" | grep -E ^\-?[0-9]?\.?[0-9]+$  
# answer is 3.2

Using in a bash script:

check=`echo "$1" | grep -E ^\-?[0-9]*\.?[0-9]+$`

if [ "$check" != '' ]; then    
  # it IS numeric
  echo "Yeap!"
else
  # it is NOT numeric.
  echo "nooop"
fi

To match JUST integers, use this:

# change check line to:
check=`echo "$1" | grep -E ^\-?[0-9]+$`

Answer 9

Just a follow up to @mary. But because I don't have enough rep, couldn't post this as a comment to that post. Anyways, here is what I used:

isnum() { awk -v a="$1" 'BEGIN {print (a == a + 0)}'; }

The function will return "1" if the argument is a number, otherwise will return "0". This works for integers as well as floats. Usage is something like:

n=-2.05e+07
res=`isnum "$n"`
if [ "$res" == "1" ]; then
     echo "$n is a number"
else
     echo "$n is not a number"
fi

Answer 10

test -z "${i//[0-9]}" && echo digits || echo no no no

${i//[0-9]} replaces any digit in the value of $i with an empty string, see man -P 'less +/parameter\/' bash. -z checks if resulting string has zero length.

if you also want to exclude the case when $i is empty, you could use one of these constructions:

test -n "$i" && test -z "${i//[0-9]}" && echo digits || echo not a number
[[ -n "$i" && -z "${i//[0-9]}" ]] && echo digits || echo not a number

Answer 11

For my problem, I only needed to ensure that a user doesn't accidentally enter some text thus I tried to keep it simple and readable

isNumber() {
    (( $1 )) 2>/dev/null
}

According to the man page this pretty much does what I want

If the value of the expression is non-zero, the return status is 0

To prevent nasty error messages for strings that "might be numbers" I ignore the error output

$ (( 2s ))
bash: ((: 2s: value too great for base (error token is "2s")

Answer 12

Old question, but I just wanted to tack on my solution. This one doesn't require any strange shell tricks, or rely on something that hasn't been around forever.

if [ -n "$(printf '%s\n' "$var" | sed 's/[0-9]//g')" ]; then
    echo 'is not numeric'
else
    echo 'is numeric'
fi

Basically it just removes all digits from the input, and if you're left with a non-zero-length string then it wasn't a number.

Answer 13

This can be achieved by using grep to see if the variable in question matches an extended regular expression.

Test integer 1120:

yournumber=1120
if echo "$yournumber" | grep -qE '^[0-9]+$'; then
    echo "Valid number."
else
    echo "Error: not a number."
fi

Output: Valid number.

Test non-integer 1120a:

yournumber=1120a
if echo "$yournumber" | grep -qE '^[0-9]+$'; then
    echo "Valid number."
else
    echo "Error: not a number."
fi

Output: Error: not a number.

---

Explanation

• The grep, the -E switch allows us to use extended regular expression '^[0-9]+$'. This regular expression means the variable should only [] contain the numbers 0-9 zero through nine from the ^ beginning to the $ end of the variable and should have at least + one character.
• The grep, the -q quiet switch turns off any output whether or not it finds anything.
• if checks the exit status of grep. Exit status 0 means success and anything greater means an error. The grep command has an exit status of 0 if it finds a match and 1 when it doesn't;

So putting it all together, in the if test, we echo the variable $yournumber and | pipe it to grep which with the -q switch silently matches the -E extended regular expression '^[0-9]+$' expression. The exit status of grep will be 0 if grep successfully found a match and 1 if it didn't. If succeeded to match, we echo "Valid number.". If it failed to match, we echo "Error: not a number.".

---

For Floats or Doubles

We can just change the regular expression from '^[0-9]+$' to '^[0-9]*\.?[0-9]+$' for floats or doubles.

Test float 1120.01:

yournumber=1120.01
if echo "$yournumber" | grep -qE '^[0-9]*\.?[0-9]+$'; then
    echo "Valid number."
else
    echo "Error: not a number."
fi

Output: Valid number.

Test float 11.20.01:

yournumber=11.20.01
if echo "$yournumber" | grep -qE '^[0-9]*\.?[0-9]+$'; then
    echo "Valid number."
else
    echo "Error: not a number."
fi

Output: Error: not a number.

---

For Negatives

To allow negative integers, just change the regular expression from '^[0-9]+$' to '^\-?[0-9]+$'.

To allow negative floats or doubles, just change the regular expression from '^[0-9]*\.?[0-9]+$' to '^\-?[0-9]*\.?[0-9]+$'.

Answer 14

I would try this:

printf "%g" "$var" &> /dev/null
if [[ $? == 0 ]] ; then
    echo "$var is a number."
else
    echo "$var is not a number."
fi

Note: this recognizes nan and inf as number.

Answer 15

Can't comment yet so I'll add my own answer, which is an extension to glenn jackman's answer using bash pattern matching.

My original need was to identify numbers and distinguish integers and floats. The function definitions deducted to:

function isInteger() {
    [[ ${1} == ?(-)+([0-9]) ]]
}

function isFloat() {
    [[ ${1} == ?(-)@(+([0-9]).*([0-9])|*([0-9]).+([0-9]))?(E?(-|+)+([0-9])) ]]
}

I used unit testing (with shUnit2) to validate my patterns worked as intended:

oneTimeSetUp() {
    int_values="0 123 -0 -123"
    float_values="0.0 0. .0 -0.0 -0. -.0 \
        123.456 123. .456 -123.456 -123. -.456
        123.456E08 123.E08 .456E08 -123.456E08 -123.E08 -.456E08 \
        123.456E+08 123.E+08 .456E+08 -123.456E+08 -123.E+08 -.456E+08 \
        123.456E-08 123.E-08 .456E-08 -123.456E-08 -123.E-08 -.456E-08"
}

testIsIntegerIsFloat() {
    local value
    for value in ${int_values}
    do
        assertTrue "${value} should be tested as integer" "isInteger ${value}"
        assertFalse "${value} should not be tested as float" "isFloat ${value}"
    done

    for value in ${float_values}
    do
        assertTrue "${value} should be tested as float" "isFloat ${value}"
        assertFalse "${value} should not be tested as integer" "isInteger ${value}"
    done

}

Notes: The isFloat pattern can be modified to be more tolerant about decimal point (@(.,)) and the E symbol (@(Ee)). My unit tests test only values that are either integer or float, but not any invalid input.

Answer 16

A clear answer has already been given by @charles Dufy and others. A pure bash solution would be using the following :

string="-12,345"
if [[ "$string" =~ ^-?[0-9]+[.,]?[0-9]*$ ]]
then
    echo $string is a number
else
    echo $string is not a number
fi

Although for real numbers it is not mandatory to have a number before the radix point.

To provide a more thorough support of floating numbers and scientific notation (many programs in C/Fortran or else will export float this way), a useful addition to this line would be the following :

string="1.2345E-67"
if [[ "$string" =~ ^-?[0-9]*[.,]?[0-9]*[eE]?-?[0-9]+$ ]]
then
    echo $string is a number
else
    echo $string is not a number
fi

Thus leading to a way to differentiate types of number, if you are looking for any specific type :

string="-12,345"
if [[ "$string" =~ ^-?[0-9]+$ ]]
then
    echo $string is an integer
elif [[ "$string" =~ ^-?[0-9]*[.,]?[0-9]*$ ]]
then
    echo $string is a float
elif [[ "$string" =~ ^-?[0-9]*[.,]?[0-9]*[eE]-?[0-9]+$ ]]
then
    echo $string is a scientific number
else
    echo $string is not a number
fi

Note: We could list the syntactical requirements for decimal and scientific notation, one being to allow comma as radix point, as well as ".". We would then assert that there must be only one such radix point. There can be two +/- signs in an [Ee] float. I have learned a few more rules from Aulu's work, and tested against bad strings such as '' '-' '-E-1' '0-0'. Here are my regex/substring/expr tools that seem to be holding up:

parse_num() {
 local r=`expr "$1" : '.*\([.,]\)' 2>/dev/null | tr -d '\n'` 
 nat='^[+-]?[0-9]+[.,]?$' \
 dot="${1%[.,]*}${r}${1##*[.,]}" \
 float='^[\+\-]?([.,0-9]+[Ee]?[-+]?|)[0-9]+$'
 [[ "$1" == $dot ]] && [[ "$1" =~ $float ]] || [[ "$1" =~ $nat ]]
} # usage: parse_num -123.456

Answer 17

[[ $1 =~ ^-?[0-9]+$ ]] && echo "number"

Don't forget - to include negative numbers!

Answer 18

I use expr. It returns a non-zero if you try to add a zero to a non-numeric value:

if expr -- "$number" + 0 > /dev/null 2>&1
then
    echo "$number is a number"
else
    echo "$number isn't a number"
fi

It might be possible to use bc if you need non-integers, but I don't believe bc has quite the same behavior. Adding zero to a non-number gets you zero and it returns a value of zero too. Maybe you can combine bc and expr. Use bc to add zero to $number. If the answer is 0, then try expr to verify that $number isn't zero.

Answer 19

One simple way is to check whether it contains non-digit characters. You replace all digit characters with nothing and check for length. If there's length it's not a number.

if [[ ! -n ${input//[0-9]/} ]]; then
    echo "Input Is A Number"
fi

Answer 20

http://tldp.org/LDP/Bash-Beginners-Guide/html/sect_04_03.html

You can also use bash's character classes.

if [[ $VAR = *[[:digit:]]* ]]; then
 echo "$VAR is numeric"
else
 echo "$VAR is not numeric"
fi

Numerics will include space, the decimal point, and "e" or "E" for floating point.

But, if you specify a C-style hex number, i.e. "0xffff" or "0XFFFF", [[:digit:]] returns true. A bit of a trap here, bash allows you do to something like "0xAZ00" and still count it as a digit (isn't this from some weird quirk of GCC compilers that let you use 0x notation for bases other than 16???)

You might want to test for "0x" or "0X" before testing if it's a numeric if your input is completely untrusted, unless you want to accept hex numbers. That would be accomplished by:

if [[ ${VARIABLE:1:2} = "0x" ]] || [[ ${VARIABLE:1:2} = "0X" ]]; then echo "$VAR is not numeric"; fi

Answer 21

I use printf as other answers mentioned, if you supply the format string "%f" or "%i" printf will do the checking for you. Easier than reinventing the checks, the syntax is simple and short and printf is ubiquitous. So its a decent choice in my opinion - you can also use the following idea to check for a range of things, its not only useful for checking numbers.

declare  -r CHECK_FLOAT="%f"  
declare  -r CHECK_INTEGER="%i"  

 ## <arg 1> Number - Number to check  
 ## <arg 2> String - Number type to check  
 ## <arg 3> String - Error message  
function check_number() { 
  local NUMBER="${1}" 
  local NUMBER_TYPE="${2}" 
  local ERROR_MESG="${3}"
  local -i PASS=1 
  local -i FAIL=0   
  case "${NUMBER_TYPE}" in 
    "${CHECK_FLOAT}") 
        if ((! $(printf "${CHECK_FLOAT}" "${NUMBER}" &>/dev/random;echo $?))); then 
           echo "${PASS}"
        else 
           echo "${ERROR_MESG}" 1>&2
           echo "${FAIL}"
        fi 
        ;;                 
    "${CHECK_INTEGER}") 
        if ((! $(printf "${CHECK_INTEGER}" "${NUMBER}" &>/dev/random;echo $?))); then 
           echo "${PASS}"
        else 
           echo "${ERROR_MESG}" 1>&2
           echo "${FAIL}"
        fi 
        ;;                 
                     *) 
        echo "Invalid number type format: ${NUMBER_TYPE} to check_number()." 1>&2
        echo "${FAIL}"
        ;;                 
   esac
} 

>$ var=45

>$ (($(check_number $var "${CHECK_INTEGER}" "Error: Found $var - An integer is required."))) && { echo "$var+5" | bc; }

Answer 22

As i had to tamper with this lately and like karttu's appoach with the unit test the most. I revised the code and added some other solutions too, try it out yourself to see the results:

#!/bin/bash

    # N={0,1,2,3,...} by syntaxerror
function isNaturalNumber()
{
 [[ ${1} =~ ^[0-9]+$ ]]
}
    # Z={...,-2,-1,0,1,2,...} by karttu
function isInteger() 
{
 [[ ${1} == ?(-)+([0-9]) ]]
}
    # Q={...,-½,-¼,0.0,¼,½,...} by karttu
function isFloat() 
{
 [[ ${1} == ?(-)@(+([0-9]).*([0-9])|*([0-9]).+([0-9]))?(E?(-|+)+([0-9])) ]]
}
    # R={...,-1,-½,-¼,0.E+n,¼,½,1,...}
function isNumber()
{
 isNaturalNumber $1 || isInteger $1 || isFloat $1
}

bools=("TRUE" "FALSE")
int_values="0 123 -0 -123"
float_values="0.0 0. .0 -0.0 -0. -.0 \
    123.456 123. .456 -123.456 -123. -.456 \
    123.456E08 123.E08 .456E08 -123.456E08 -123.E08 -.456E08 \
    123.456E+08 123.E+08 .456E+08 -123.456E+08 -123.E+08 -.456E+08 \
    123.456E-08 123.E-08 .456E-08 -123.456E-08 -123.E-08 -.456E-08"
false_values="blah meh mooh blah5 67mooh a123bc"

for value in ${int_values} ${float_values} ${false_values}
do
    printf "  %5s=%-30s" $(isNaturalNumber $value) ${bools[$?]} $(printf "isNaturalNumber(%s)" $value)
    printf "%5s=%-24s" $(isInteger $value) ${bools[$?]} $(printf "isInteger(%s)" $value)
    printf "%5s=%-24s" $(isFloat $value) ${bools[$?]} $(printf "isFloat(%s)" $value)
    printf "%5s=%-24s\n" $(isNumber $value) ${bools[$?]} $(printf "isNumber(%s)" $value)
done

So isNumber() includes dashes, commas and exponential notation and therefore returns TRUE on integers & floats where on the other hand isFloat() returns FALSE on integer values and isInteger() likewise returns FALSE on floats. For your convenience all as one liners:

isNaturalNumber() { [[ ${1} =~ ^[0-9]+$ ]]; }
isInteger() { [[ ${1} == ?(-)+([0-9]) ]]; }
isFloat() { [[ ${1} == ?(-)@(+([0-9]).*([0-9])|*([0-9]).+([0-9]))?(E?(-|+)+([0-9])) ]]; }
isNumber() { isNaturalNumber $1 || isInteger $1 || isFloat $1; }

Answer 23

I like Alberto Zaccagni's answer.

if [ "$var" -eq "$var" ] 2>/dev/null; then

Important prerequisites: - no subshells spawned - no RE parsers invoked - most shell applications don't use real numbers

But if $var is complex (e.g. an associative array access), and if the number will be a non-negative integer (most use-cases), then this is perhaps more efficient?

if [ "$var" -ge 0 ] 2> /dev/null; then ..

Answer 24

To catch negative numbers:

if [[ $1 == ?(-)+([0-9.]) ]]
    then
    echo number
else
    echo not a number
fi

Answer 25

You could use "let" too like this :

[ ~]$ var=1
[ ~]$ let $var && echo "It's a number" || echo "It's not a number"
It\'s a number
[ ~]$ var=01
[ ~]$ let $var && echo "It's a number" || echo "It's not a number"
It\'s a number
[ ~]$ var=toto
[ ~]$ let $var && echo "It's a number" || echo "It's not a number"
It\'s not a number
[ ~]$ 

But I prefer use the "=~" Bash 3+ operator like some answers in this thread.

Answer 26

Almost as you want in syntax. Just need a function isnumber:

#!/usr/bin/bash

isnumber(){
  num=$1
  if [ -z "${num##*[!0-9]*}" ]; 
    then return 1
  else
    return 0
  fi
}

$(isnumber "$1") && VAR=$1 || echo "need a number";
echo "VAR is $VAR"

test:

$ ./isnumtest 10
VAR is 10
$ ./isnumtest abc10
need a number
VAR is 

UPDATE 2024 (it still doesn't support floating point numbers)

#!/usr/bin/bash

isnumber(){
  if [ -z "$1" ]; then
    echo "{empty string} isn't number"
    return 1
  elif [ -z "${1##*[!0-9]*}" ]; then
    echo "$1 isn't number"
    return 1
  else
    echo "$1 is number" 
    return 0
  fi
}

isnumber "$1"

Answer 27

printf '%b' "-123\nABC" | tr '[:space:]' '_' | grep -q '^-\?[[:digit:]]\+$' && echo "Integer." || echo "NOT integer."

Remove the -\? in grep matching pattern if you don't accept negative integer.

Answer 28

I use the following (for integers):

## ##### constants
##
## __TRUE - true (0)
## __FALSE - false (1)
##
typeset -r __TRUE=0
typeset -r __FALSE=1

## --------------------------------------
## isNumber
## check if a value is an integer 
## usage: isNumber testValue 
## returns: ${__TRUE} - testValue is a number else not
##
function isNumber {
  typeset TESTVAR="$(echo "$1" | sed 's/[0-9]*//g' )"
  [ "${TESTVAR}"x = ""x ] && return ${__TRUE} || return ${__FALSE}
}

isNumber $1 
if [ $? -eq ${__TRUE} ] ; then
  print "is a number"
fi

Answer 29

I tried ultrasawblade's recipe as it seemed the most practical to me, and couldn't make it work. In the end i devised another way though, based as others in parameter substitution, this time with regex replacement:

[[ "${var//*([[:digit:]])}" ]]; && echo "$var is not numeric" || echo "$var is numeric"

It removes every :digit: class character in $var and checks if we are left with an empty string, meaning that the original was only numbers.

What i like about this one is its small footprint and flexibility. In this form it only works for non-delimited, base 10 integers, though surely you can use pattern matching to suit it to other needs.

Answer 30

I found quite a short version:

function isnum()
{
    return `echo "$1" | awk -F"\n" '{print ($0 != $0+0)}'`
}