Extract list values that don’t equal one

Question

I need help stripping integers from a list. For example, if I have the list [1,1,3,1,9,1,1,1,30] how could I extract the 3, 9 and 30?

Answer 1

Thos could be accomplished with a list comprehension and a condition

list_of_ints = [1, 1, 3, 1, 9, 1, 1, 1, 30]
all_integers_except_ones = [i for i in list_of_ints if i != 1]
print(all_integers_except_ones)

outputs the list:

[3, 9, 30]

Answer 2

 l = [1,1,3,1,9,1,1,1,30]
[e for e in l if e != 1]

gives

[3, 9, 30]

Answer 3

I would use the filter() method with a lambda expression:

    mostly_ones = [1, 1, 3, 1, 9, 1, 1, 1, 30]
    list(filter(lambda x : x != 1, mostly_ones))

Output:

[3, 9, 30]

Answer 4

your question in not complete, but what I understood is that you want to remove the duplication from the list. well if you want to do that, just create and new empty list and append any item that is not in the new list to it.

list1 = [1,1,3,1,9,1,1,1,30]

new_list = [ ]

for item in list1:

if item not in new_list:
    new_list.append (item)

print (new_list)

or you can use count() method and remove() method to Remove the duplication.