How to convert vector to array

Question

How do I convert a std::vector<double> to a double array[]?

Answer 1

There's a fairly simple trick to do so, since the spec now guarantees vectors store their elements contiguously:

std::vector<double> v;
double* a = &v[0];

Answer 2

What for? You need to clarify: Do you need a pointer to the first element of an array, or an array?

If you're calling an API function that expects the former, you can do do_something(&v[0], v.size()), where v is a vector of doubles. The elements of a vector are contiguous.

Otherwise, you just have to copy each element:

double arr[100];
std::copy(v.begin(), v.end(), arr);

Ensure not only thar arr is big enough, but that arr gets filled up, or you have uninitialized values.

Answer 3

For C++11, vector.data() will do the trick.

Answer 4

vector<double> thevector;
//...
double *thearray = &thevector[0];

This is guaranteed to work by the standard, however there are some caveats: in particular take care to only use thearray while thevector is in scope.

Answer 5

As to std::vector<int> vec, vec to get int*, you can use two method:

1. int* arr = &vec[0];

2. int* arr = vec.data();

If you want to convert any type T vector to T* array, just replace the above int to T.

I will show you why does the above two works, for good understanding?

std::vector is a dynamic array essentially.

Main data member as below:

template <class T, class Alloc = allocator<T>>
class vector{
    public:
        typedef T          value_type;
        typedef T*         iterator;
        typedef T*         pointer;
        //.......
    private:
        pointer start_;
        pointer finish_;
        pointer end_of_storage_;

    public:
        vector():start_(0), finish_(0), end_of_storage_(0){}
    //......
}

The range (start_, end_of_storage_) is all the array memory the vector allocate;

The range(start_, finish_) is all the array memory the vector used;

The range(finish_, end_of_storage_) is the backup array memory.

For example, as to a vector vec. which has {9, 9, 1, 2, 3, 4} is pointer may like the below.

So &vec[0] = start_ (address.) (start_ is equivalent to int* array head)

In c++11 the data() member function just return start_

pointer data()
{ 
     return start_; //(equivalent to `value_type*`, array head)
}

Answer 6

Vectors effectively are arrays under the skin. If you have a function:

void f( double a[]);

you can call it like this:

vector <double> v;
v.push_back( 1.23 )
f( &v[0] );

You should not ever need to convert a vector into an actual array instance.

Answer 7

std::vector<double> vec;
double* arr = vec.data();

Answer 8

We can do this using data() method. C++11 provides this method.

Code Snippet

#include<bits/stdc++.h>
using namespace std;


int main()
{
  ios::sync_with_stdio(false);

  vector<int>v = {7, 8, 9, 10, 11};
  int *arr = v.data();

  for(int i=0; i<v.size(); i++)
  {
    cout<<arr[i]<<" ";
  }

  return 0;
}

Answer 9

If you have a function, then you probably need this:foo(&array[0], array.size());. If you managed to get into a situation where you need an array then you need to refactor, vectors are basically extended arrays, you should always use them.

Answer 10

You can do some what like this

vector <int> id;
vector <double> v;

if(id.size() > 0)
{
    for(int i = 0; i < id.size(); i++)
    {
        for(int j = 0; j < id.size(); j++)
        {
            double x = v[i][j];
            cout << x << endl;
        }
    }
}