To access to the first argument of a function, I use
func() { echo $1; }
How to access directly to the last argument of a function in ash?
I do not want to use loops neither functions or complicated commands
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1 Answer
You can use $($#).
$# is the number of arguments (which is equal to the index of the last argument), so $($#) is the last argument.
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If you have to enter 25 space characters before your final question mark, that's a very good indication that your answer is not an answer. Use words to explain what you mean by those 4 characters.– jbaumsCommented Feb 20, 2015 at 10:30
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There's nothing much to explain : $# is the number of arguments, which is the index of the last argument, so $($#) is the last argument.– sssssCommented Feb 20, 2015 at 10:37
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This is wrong. Round parentheses are used for command substitution. In theory,
${$#}with curly brackets could work, but it doesn't without additional indirection (so basicallyeval \${$#}with all the usual caveats againsteval).– tripleeeCommented Apr 30, 2015 at 8:35