506

I've heard it said that multiline lambdas can't be added in Python because they would clash syntactically with the other syntax constructs in Python. I was thinking about this on the bus today and realized I couldn't think of a single Python construct that multiline lambdas clash with. Given that I know the language pretty well, this surprised me.

Now, I'm sure Guido had a reason for not including multiline lambdas in the language, but out of curiosity: what's a situation where including a multiline lambda would be ambiguous? Is what I've heard true, or is there some other reason that Python doesn't allow multiline lambdas?

10
  • 47
    tl;dr version: because Python is a lazy language without { } blocks and so this was not allowed in order to keep a consistent syntactical design.
    – Andrew
    Commented Aug 11, 2017 at 15:02
  • 31
    Also: I'm thoroughly surprised no one mentioned this in the answers... You can end lines with the \ character in Python and continue onto the next line... This information kinda supersedes this whole question so...
    – Andrew
    Commented Aug 11, 2017 at 16:48
  • 1
  • 3
    "syntactical design"
    – nicolas
    Commented Nov 18, 2019 at 16:13
  • 2
    @chepner Except that the def can not line inline with the logic it is intended for use: you have to go place it somewhere else and then the reader has to go hunt for it. Having a def for code that is only used once is a serious deficiency with the python language: those should only be needed for code re-use. Commented Mar 28, 2020 at 17:30

26 Answers 26

848

Guido van Rossum (the inventor of Python) answers this exact question himself in an old blog post.
Basically, he admits that it's theoretically possible, but that any proposed solution would be un-Pythonic:

"But the complexity of any proposed solution for this puzzle is immense, to me: it requires the parser (or more precisely, the lexer) to be able to switch back and forth between indent-sensitive and indent-insensitive modes, keeping a stack of previous modes and indentation level. Technically that can all be solved (there's already a stack of indentation levels that could be generalized). But none of that takes away my gut feeling that it is all an elaborate Rube Goldberg contraption."

17
  • 140
    Why isn't this the top answer? It's not about the technical reasons, it's a design choice, as clearly stated by the inventor. Commented Nov 15, 2011 at 21:33
  • 22
    @DanAbramov because the OP didn't log in for years probably. Commented Jan 10, 2013 at 8:26
  • 77
    Guido's answer is just another reason I wish Python didn't depend on indentation to define blocks. Commented Apr 16, 2014 at 14:12
  • 33
    I'm not sure I'd call "gut feeling" a design choice. ;) Commented Dec 4, 2015 at 21:04
  • 12
    @leo-the-manic Because the word "design" implies some level of intentionality and care. Many languages do provide multi-line lambdas and they are very much an intentional part of the design. Python's lack of them actually has drastic implications and significantly complicates the surface syntax. (For example, both decorators and context managers could be obviated by multiline lambdas.) So this "gut feeling" is not particularly satisfying in the presence of so much existing wisdom to the contrary. Instead of complicating the parser, it complicates every Python program ever written instead. Commented Jan 27, 2017 at 17:33
183

Look at the following:

map(multilambda x:
      y=x+1
      return y
   , [1,2,3])

Is this a lambda returning (y, [1,2,3]) (thus map only gets one parameter, resulting in an error)? Or does it return y? Or is it a syntax error, because the comma on the new line is misplaced? How would Python know what you want?

Within the parens, indentation doesn't matter to python, so you can't unambiguously work with multilines.

This is just a simple one, there's probably more examples.

8
  • 137
    they could force the use of parentheses if you want to return a tuple from a lambda. IMO, this should have always been enforced to prevent such ambiguities, but oh well.
    – mpen
    Commented Jul 28, 2012 at 23:28
  • 38
    This is a simple ambiguity that must be solved by adding an extra set of parens, something that exists in many places already, e.g. generator expressions surrounded by other arguments, calling a method on an integer literal (although this need not be the case since a function name can't begin with a digit), and of course single-line lambdas as well (which may be long expressions written on multiple lines). Multi-line lambdas would not be especially different from these cases that it warrants excluding them on that basis. This is the real answer.
    – nmclean
    Commented Mar 7, 2014 at 13:41
  • 17
    I like how there are gazillion languages that deal with it no fret, but somehow there are some deep reasons why it's supposedly very hard if not impossible
    – nicolas
    Commented Nov 18, 2019 at 16:07
  • 4
    @nicolas that's python in a nutshell Commented Dec 20, 2019 at 7:57
  • 3
    For functional programming, I'd go with Scala over Python any day.
    – lostsoul29
    Commented Nov 25, 2020 at 16:20
88

This is generally very ugly (but sometimes the alternatives are even more ugly), so a workaround is to make a braces expression:

lambda: (
    doFoo('abc'),
    doBar(123),
    doBaz())

It won't accept any assignments though, so you'll have to prepare data beforehand. The place I found this useful is the PySide wrapper, where you sometimes have short callbacks. Writing additional member functions would be even more ugly. Normally you won't need this.

Example:

pushButtonShowDialog.clicked.connect(
    lambda: (
    field1.clear(),
    spinBox1.setValue(0),
    diag.show())
8
  • 3
    My boss was just asking for something like this in our PyQt application. Awesome!
    – TheGerm
    Commented Jan 26, 2015 at 23:55
  • 1
    Thanks for this, I was also looking for a good way to use short (but still multiline) lambdas as callbacks for our PySide UI. Commented Nov 18, 2016 at 3:19
  • And now I've seen this it instantly suggested using lambda arg and setattr(arg, 'attr','value') to subvert "no assignments ...". And then there's short-circuit evaluation of and and or ... it's the Javascript that does it. Sinks roots into you, like ivy into a wall. I almost hope I forget this over Xmas.
    – nigel222
    Commented Dec 20, 2018 at 17:47
  • quite clever - and quite readable. Now - about those (missing..) assignments .. Commented Mar 9, 2020 at 15:44
  • 1
    @nigel222 why feel ashamed? The python language is fundamentally crippled - but it's the one used anyways for much of data science. So we make adjustments. Finding ways to do side effects (often enough simply printing /logging!) and assignments (often enough to just intermediate vars!) should be well handled by the language. But they aren't even supported (at least if you follow PEP guidelines) Commented Mar 9, 2020 at 15:45
22

A couple of relevant links:

For a while, I was following the development of Reia, which was initially going to have Python's indentation based syntax with Ruby blocks too, all on top of Erlang. But, the designer wound up giving up on indentation sensitivity, and this post he wrote about that decision includes a discussion about problems he ran into with indentation + multi-line blocks, and an increased appreciation he gained for Guido's design issues/decisions:

http://www.unlimitednovelty.com/2009/03/indentation-sensitivity-post-mortem.html

Also, here's an interesting proposal for Ruby-style blocks in Python I ran across where Guido posts a response w/o actually shooting it down (not sure whether there has been any subsequent shoot down, though):

http://tav.espians.com/ruby-style-blocks-in-python.html

0
19

Let me present to you a glorious but terrifying hack:

import types

def _obj():
  return lambda: None

def LET(bindings, body, env=None):
  '''Introduce local bindings.
  ex: LET(('a', 1,
           'b', 2),
          lambda o: [o.a, o.b])
  gives: [1, 2]

  Bindings down the chain can depend on
  the ones above them through a lambda.
  ex: LET(('a', 1,
           'b', lambda o: o.a + 1),
          lambda o: o.b)
  gives: 2
  '''
  if len(bindings) == 0:
    return body(env)

  env = env or _obj()
  k, v = bindings[:2]
  if isinstance(v, types.FunctionType):
    v = v(env)

  setattr(env, k, v)
  return LET(bindings[2:], body, env)

You can now use this LET form as such:

map(lambda x: LET(('y', x + 1,
                   'z', x - 1),
                  lambda o: o.y * o.z),
    [1, 2, 3])

which gives: [0, 3, 8]

4
19

I'm guilty of practicing this dirty hack in some of my projects which is bit simpler:

    lambda args...:( expr1, expr2, expr3, ...,
            exprN, returnExpr)[-1]

I hope you can find a way to stay pythonic but if you have to do it this less painful than using exec and manipulating globals.

3
  • Yep, almost there. Together with assignment expression it makes it a lot more usefull. Commented Jan 21, 2021 at 23:32
  • 1
    If you define a function def multiline(*expressions): return expressions[-1] then you can write lambda args...: multiline(expr1, ..., returnExpr) which reads a bit less strangely.
    – user118967
    Commented May 30, 2022 at 22:00
  • It's ugly. But it's works.
    – Zhuo YING
    Commented Jun 29, 2022 at 8:05
17

[Edit Edit] Since this question is somehow still active 12 years after being asked. I will continue the tradition of amending my answer every 4 years or so.

Firstly, the question was how does multi-line lambda clash with Python. The accepted answer shows how with a simple example. The highly rated answer I linked below some years ago answers the question of "Why is it not a part of Python"--this answer is perhaps more satisfying to those who believe that the existing examples of "clashing" are not enough to make multi-line lambda impossible to implement in Python.

In previous iterations of this answer I discussed how to implement multi-line lambda into Python as is. I've since removed that part, because it was a flurry of bad practices. You may see it in the edit history of this answer if you wish.

However the answer to "Why not?", being "because Rossum said so" can still be a source of frustration. So lets see if it could be engineered around the counter example given by user balpha:

map(lambda x:
        y=x+1 # <-- this line defines the outmost indent level*
        for i in range(12):
            y+=12
        return y
   , [1,2,3])

#*By convention it is always one-indent past the 'l' in lambda

As for the return value we have that the following is non-permissible in python:

def f():
  return 3
, [1,2,3]

So by the same logic, "[1,2,3]" should not be part of the return value. Let's try it this way instead:

map(lambda x:
        y=x+1                    # part of lambda block
        for i in range(12):      # part of lambda block
            y+=12                # part of lambda block
        return y, [1,2,3])       # part of lambda block

This one's trickier, but since the lambda block has a clearly defined beginning (the token 'lambda') yet no clear ending, I would argue anything that is on the same line as part of a lambda block is also part of the lambda block.

One might imagine some features that can identify closing parenthesis or even inference based on the number of tokens expected by the enclosing element. In general, the above expression does not seem totally impossible to parse, but it may be a bit of a challenge.

To simplify things, you could separate all characters not intended to be part of the block:

map(lambda x:
        y=x+1                    # part of lambda block
        for i in range(12):      # part of lambda block
            y+=12                # part of lambda block
        return y                 # part of lambda block
, [1,2,3]) # argument separator, second argument, and closing paren for map

Back to where we were but this time it is unambiguous, because the last line is behind the lowest indent-depth for the lambda block. Single line lambda would be a special case (identified by the lack of an immediate newline after the color), that behaves the same as it does now.

This is not to say that it necessarily should be a part of Python--but it is a quick illustration that is perhaps is possible with some changes in the language.

[Edit] Read this answer. It explains why multi-line lambda is not a thing.

Simply put, it's unpythonic. From Guido van Rossum's blog post:

I find any solution unacceptable that embeds an indentation-based block in the middle of an expression. Since I find alternative syntax for statement grouping (e.g. braces or begin/end keywords) equally unacceptable, this pretty much makes a multi-line lambda an unsolvable puzzle.

0
10

Let me also throw in my two cents about different workarounds.

How is a simple one-line lambda different from a normal function? I can think only of lack of assignments, some loop-like constructs (for, while), try-except clauses... And that's it? We even have a ternary operator - cool! So, let's try to deal with each of these problems.

Assignments

Some guys here have rightly noted that we should take a look at lisp's let form, which allows local bindings. Actually, all the non state-changing assignments can be performed only with let. But every lisp programmer knows that let form is absolutely equivalent to call to a lambda function! This means that

(let ([x_ x] [y_ y])
  (do-sth-with-x-&-y x_ y_))

is the same as

((lambda (x_ y_)
   (do-sth-with-x-&-y x_ y_)) x y)

So lambdas are more than enough! Whenever we want to make a new assignment we just add another lambda and call it. Consider this example:

def f(x):
    y = f1(x)
    z = f2(x, y)
    return y,z

A lambda version looks like:

f = lambda x: (lambda y: (y, f2(x,y)))(f1(x))

You can even make the let function, if you don't like the data being written after actions on the data. And you can even curry it (just for the sake of more parentheses :) )

let = curry(lambda args, f: f(*args))
f_lmb = lambda x: let((f1(x),), lambda y: (y, f2(x,y)))
# or:
f_lmb = lambda x: let((f1(x),))(lambda y: (y, f2(x,y)))

# even better alternative:
let = lambda *args: lambda f: f(*args)
f_lmb = lambda x: let(f1(x))(lambda y: (y, f2(x,y)))

So far so good. But what if we have to make reassignments, i.e. change state? Well, I think we can live absolutely happily without changing state as long as task in question doesn't concern loops.

Loops

While there's no direct lambda alternative for loops, I believe we can write quite generic function to fit our needs. Take a look at this fibonacci function:

def fib(n):
    k = 0
    fib_k, fib_k_plus_1 = 0, 1
    while k < n:
        k += 1
        fib_k_plus_1, fib_k = fib_k_plus_1 + fib_k, fib_k_plus_1
    return fib_k

Impossible in terms of lambdas, obviously. But after writing a little yet useful function we're done with that and similar cases:

def loop(first_state, condition, state_changer):
    state = first_state
    while condition(*state):
        state = state_changer(*state)
    return state

fib_lmb = lambda n:\
            loop(
              (0,0,1),
              lambda k, fib_k, fib_k_plus_1:\
                k < n,
              lambda k, fib_k, fib_k_plus_1:\
                (k+1, fib_k_plus_1, fib_k_plus_1 + fib_k))[1]

And of course, one should always consider using map, reduce and other higher-order functions if possible.

Try-except and other control structs

It seems like a general approach to this kind of problems is to make use of lazy evaluation, replacing code blocks with lambdas accepting no arguments:

def f(x):
    try:    return len(x)
    except: return 0
# the same as:
def try_except_f(try_clause, except_clause):
    try: return try_clause()
    except: return except_clause()
f = lambda x: try_except_f(lambda: len(x), lambda: 0)
# f(-1) -> 0
# f([1,2,3]) -> 3

Of course, this is not a full alternative to try-except clause, but you can always make it more generic. Btw, with that approach you can even make if behave like function!

Summing up: it's only natural that everything mentioned feels kinda unnatural and not-so-pythonically-beautiful. Nonetheless - it works! And without any evals and other trics, so all the intellisense will work. I'm also not claiming that you shoud use this everywhere. Most often you'd better define an ordinary function. I only showed that nothing is impossible.

3
  • It's crazy! Cool!
    – plinyar
    Commented Dec 7, 2020 at 19:14
  • @aoeu256 I don't quite get it, could you provide some example/doc, please?
    – heinwol
    Commented Mar 25, 2021 at 11:20
  • This is very helpful. While I would never write real code like this, I use a number of tools that incorporate python as an extension language, and which require expressions for certain inputs. These tips let me stretch the boundaries of what I can enter as an expression. My record so far includes converting 300 lines of procedural code into a single functional expression.
    – pavon
    Commented Mar 31, 2022 at 20:58
10

After Python3.8, there is another method for local binding

lambda x: (
    y := x + 1,
    y ** 2
)[-1]

For Loop

lambda x: (
    y := x ** 2,
    [y := y + x for _ in range(10)],
    y
)[-1]

If Branch

lambda x: (
    y := x ** 2,
    x > 5 and [y := y + x for _ in range(10)],
    y
)[-1]

Or

lambda x: (
    y := x ** 2,
    [y := y + x for _ in range(10)] if x > 5 else None,
    y
)[-1]

While Loop

import itertools as it
lambda x: (
    l := dict(y = x ** 2),
    cond := lambda: l['y'] < 100,
    body := lambda: l.update(y = l['y'] + x),
    *it.takewhile(lambda _: cond() and (body(), True)[-1], it.count()),
    l['y']
)[-1]

Or

import itertools as it
from types import SimpleNamespace as ns
lambda x: (
    l := ns(y = x ** 2),
    cond := lambda: l.y < 100,
    body := lambda: vars(l).update(y = l.y + x),
    *it.takewhile(lambda _: cond() and (body(), True)[-1], it.count()),
    l.y
)[-1]

Or

import itertools as it
lambda x: (
    y := x ** 2,
    *it.takewhile(lambda t: t[0],
    ((
    pred := y < 100,
    pred and (y := y + x))
    for _ in it.count())),
    y
)[-1]
6

Let me try to tackle @balpha parsing problem. I would use parentheses around the multiline lamda. If there is no parentheses, the lambda definition is greedy. So the lambda in

map(lambda x:
      y = x+1
      z = x-1
      y*z,
    [1,2,3]))

returns a function that returns (y*z, [1,2,3])

But

map((lambda x:
      y = x+1
      z = x-1
      y*z)
    ,[1,2,3]))

means

map(func, [1,2,3])

where func is the multiline lambda that return y*z. Does that work?

4
  • 1
    I'm thinking the top one should return map(func, [1,2,3]) and the bottom one should be an error because the map function doesn't have enough arguments. Also there are some extra parenthesis in the code.
    – Samie Bee
    Commented Dec 1, 2016 at 20:28
  • dropping that into pycharm running python2.7.13 it gives a syntax error.
    – simbo1905
    Commented Sep 11, 2018 at 15:04
  • extra parenthesis
    – Samie Bee
    Commented Nov 24, 2018 at 6:35
  • Well, we have expression assignments now, it could work, please check my answer below Commented Jan 21, 2021 at 23:31
5

(For anyone still interested in the topic.)

Consider this (includes even usage of statements' return values in further statements within the "multiline" lambda, although it's ugly to the point of vomiting ;-)

>>> def foo(arg):
...     result = arg * 2;
...     print "foo(" + str(arg) + ") called: " + str(result);
...     return result;
...
>>> f = lambda a, b, state=[]: [
...     state.append(foo(a)),
...     state.append(foo(b)),
...     state.append(foo(state[0] + state[1])),
...     state[-1]
... ][-1];
>>> f(1, 2);
foo(1) called: 2
foo(2) called: 4
foo(6) called: 12
12
1
  • This doesn't work when called a second time with different parameters and causes a memory leak unless the first line is state.clear() since default arguments are only created once when the function is created. Commented Aug 10, 2018 at 18:12
4

Here's a more interesting implementation of multi line lambdas. It's not possible to achieve because of how python use indents as a way to structure code.

But luckily for us, indent formatting can be disabled using arrays and parenthesis.

As some already pointed out, you can write your code as such:

lambda args: (expr1, expr2,... exprN)

In theory if you're guaranteed to have evaluation from left to right it would work but you still lose values being passed from one expression to an other.

One way to achieve that which is a bit more verbose is to have

lambda args: [lambda1, lambda2, ..., lambdaN]

Where each lambda receives arguments from the previous one.

def let(*funcs):
    def wrap(args):
        result = args                                                                                                                                                                                                                         
        for func in funcs:
            if not isinstance(result, tuple):
                result = (result,)
            result = func(*result)
        return result
    return wrap

This method let you write something that is a bit lisp/scheme like.

So you can write things like this:

let(lambda x, y: x+y)((1, 2))

A more complex method could be use to compute the hypotenuse

lst = [(1,2), (2,3)]
result = map(let(
  lambda x, y: (x**2, y**2),
  lambda x, y: (x + y) ** (1/2)
), lst)

This will return a list of scalar numbers so it can be used to reduce multiple values to one.

Having that many lambda is certainly not going to be very efficient but if you're constrained it can be a good way to get something done quickly then rewrite it as an actual function later.

4

In Python 3.8/3.9 there is Assignment Expression, so it could be used in lambda, greatly expanding functionality

E.g., code

#%%
x = 1
y = 2

q = list(map(lambda t: (
    tx := t*x,
    ty := t*y,
    tx+ty
)[-1], [1, 2, 3]))

print(q)

will print [3, 6, 9]

3
  • This seems like the best solution by far! Why is it not upvoted more?
    – Venryx
    Commented Apr 3, 2022 at 22:56
  • Here is a Python code sandbox showing it in action!: replit.com/@Venryx/PythonMultiLineLambdas#main.py
    – Venryx
    Commented Apr 3, 2022 at 22:56
  • Possible, but it is weird, the syntax is changing, = becomes := and have to end the line in a comma,
    – 27px
    Commented Aug 8, 2022 at 4:02
2

On the subject of ugly hacks, you can always use a combination of exec and a regular function to define a multiline function like this:

f = exec('''
def mlambda(x, y):
    d = y - x
    return d * d
''', globals()) or mlambda

You can wrap this into a function like:

def mlambda(signature, *lines):
    exec_vars = {}
    exec('def mlambda' + signature + ':\n' + '\n'.join('\t' + line for line in lines), exec_vars)
    return exec_vars['mlambda']

f = mlambda('(x, y)',
            'd = y - x',
            'return d * d')
2

I know it is an old question, but for the record here is a kind of a solution to the problem of multiline lambda problem in which the result of one call is consumed by another call.

I hope it is not super hacky, since it is based only on standard library functions and uses no dunder methods.

Below is a simple example in which we start with x = 3 and then in the first line we add 1 and then in the second line we add 2 and get 6 as the output.

from functools import reduce

reduce(lambda data, func: func(data), [
    lambda x: x + 1,
    lambda x: x + 2
], 3)

## Output: 6
3
  • 1
    It's not hacky, in fact several years back I just made the above a convenience function: the args are the apply(list, [fns]). but it's still awkward. The root of the problem is that lambdas just suck in python. Single expression only, one line only, and even the keyword lambda gets real old real fast Commented Nov 2, 2020 at 12:42
  • Actually, it's a popular approach. The package toolz have this and other fancy functional stuff. With it, your example might be rewritten as: toolz.pipe(3, lambda x: x + 1, lambda x: x + 3).
    – heinwol
    Commented Dec 7, 2020 at 15:30
  • you could use assignment expressions in lambda for that, don't need to chain lambdas, check my answer below Commented Jan 21, 2021 at 23:34
0

I was just playing a bit to try to make a dict comprehension with reduce, and come up with this one liner hack:

In [1]: from functools import reduce
In [2]: reduce(lambda d, i: (i[0] < 7 and d.__setitem__(*i[::-1]), d)[-1], [{}, *{1:2, 3:4, 5:6, 7:8}.items()])                                                                                                                                                                 
Out[3]: {2: 1, 4: 3, 6: 5}

I was just trying to do the same as what was done in this Javascript dict comprehension: https://stackoverflow.com/a/11068265

0

You can simply use slash (\) if you have multiple lines for your lambda function

Example:

mx = lambda x, y: x if x > y \
     else y
print(mx(30, 20))

Output: 30
1
  • The question concerns itself with using more than 1 expression rather than more than 1 literal line.
    – TZubiri
    Commented Oct 30, 2019 at 21:27
0

I am starting with python but coming from Javascript the most obvious way is extract the expression as a function....

Contrived example, multiply expression (x*2) is extracted as function and therefore I can use multiline:

def multiply(x):
  print('I am other line')
  return x*2

r = map(lambda x : multiply(x), [1, 2, 3, 4])
print(list(r))

https://repl.it/@datracka/python-lambda-function

Maybe it does not answer exactly the question if that was how to do multiline in the lambda expression itself, but in case somebody gets this thread looking how to debug the expression (like me) I think it will help

2
  • 3
    Why would I do that and not simply write map(multiply, [1, 2, 3])?
    – thothal
    Commented Mar 19, 2020 at 10:13
  • 1
    Then you have to go hunt for wherever multiply() is. It makes one lose the flow of the code, unlike javascript in which the map logic is contained right there within the following block Commented Nov 2, 2020 at 12:45
0

We can use inner classes to obtain multi-statement lambdas:

class Foo():
    def __init__(self, x):
        self.x=x

def test1(i):
    i.x += 1
    class closure():
        @staticmethod
        def call():
          i.x += 1
          print('lamba one value:', i.x)
    return closure.call

def test2(i):
    class closure():
        @staticmethod
        def call():
          i.x += 1
          print('lambda two value:', i.x)
    return closure.call

u = Foo(10)
test1(u)() # print 12
u = Foo(20)
test2(u)() # print 21
0

My hacky solution how to achieve multiline lambdas:

import re


def inline_func(code: str, globals_=None, locals_=None):
    if globals_ is None: globals_ = globals()
    if locals_ is None: locals_ = locals()

    lines = code.splitlines(keepends=True)
    indent = None
    func_name = None
    for i, line in enumerate(lines):
        if indent is None:
            if m := re.match(r'^(\s*)def\s+(\w+)', line):
                indent, func_name = m.groups()
                lines[i] = line.replace(indent, '', 1)
        else:
            lines[i] = line.replace(indent, '', 1)

    code = ''.join(lines).strip()
    exec(code, globals_, locals_)
    return locals_[func_name]


assert list(map(inline_func(
    '''
    def f(x):
        return (x + 1) ** 2
    '''
    ),
    range(3)
)) == [1, 4, 9]

It takes textual definition of a function, creates real callable function and returns it. And with IDEs like Pycharm which can inject syntax highlighting into strings, this solution is not even that bad as it can be edited as normal code:)

0

Not multiline but multioperation lambda (working on python 3.8+)

>>> foo = lambda x: (x := x**2, x + 1)[-1] # f = x^2 + 1
>>> foo(4)
17
0

I found a fairly nice workaround that works for me: Because Python is fully dynamic, you can re-use def's! It's not quite as terse, but it's the next best thing. E.g.:

thing1 = Thing()
def doThing():
  pass
thing1.func = doThing

thing2 = Thing()
def doThing():
  print("thingy")
thing2.func = doThing

So in this case, doThing is acting like a multi-line lambda. What's also cool is that you don't even have to define func or do any preparation work in the Thing class here if you don't want to.

In other words, you have a full-on Decorator Pattern + Mixin Pattern combo capability this way, so you can setup fully dynamically-created classes with as little or as much structure to them as you desire!

But the main reason to use this approach, for those looking just to do multi-line lambda's in Python, is because now you can assign a bunch of different functions in a semi-inline sort of way, without having to come up with clever names for each.

1
  • Now, if you're wanting to "bind" the class instance's self to the function, like JavaScript's .bind()... Use MethodType() from the types module: stackoverflow.com/a/77629912/1599699
    – Andrew
    Commented Dec 9, 2023 at 2:16
0

Some solutions already point out, how assignments can be done in multiline lamdas with pythons 3.8+ assignment expressions. To extend a bit on this, now here is what one can do help the type-checker with multiline lambdas (python 3.12+):

Ts = TypeVarTuple("Ts")
class Lambda[**P, R]:
    def __init__(self, c: Callable[P, tuple[*Ts, R]]):
        self.c = c

    def __call__(self, *args: P.args, **kwargs: P.kwargs) -> R:
        return self.c(*args, **kwargs)[-1]

l = Lambda[[Iterable, int], int](lambda it, y: (
    it := [y*abs(z) for z in it],
    reduce(lambda a, b: a + b, it)
    ))

print(l(range(5), 2))

I also like to specify the parameters first, if I execute the lambda directly, it goes nice with the order of things

Ts = TypeVarTuple("Ts")
class L2[**P, R]:
    def __init__(self, *args: P.args, **kwargs: P.kwargs):
        self.args = args
        self.kwargs = kwargs

    def __call__(self, c: Callable[P, tuple[*Ts, R]]) -> R:
        return c(*self.args, **self.kwargs)[-1]

x = L2[[int, int], int](2, 3)(lambda x, y: (
    z := x + y,
    x * z
    ))

One other annotation to make: If You accidentially mess up with the assignment operators = insteand of := and possibly other things in the syntax, You will probably get quite unhelpful error messages, so be warned.

-1

One safe method to pass any number of variables between lambda items:

print((lambda: [
    locals().__setitem__("a", 1),
    locals().__setitem__("b", 2),
    locals().__setitem__("c", 3),
    locals().get("a") + locals().get("b") + locals().get("c")
])()[-1])

Output: 6

1
-1

Multiline lambdas do exist in Python.

With Python, whenever you want multiline , think parenthesis.

lambda a, b, c, d: (
    a + b + c + d
)

Short example:

l = [1, 2, 3, 4]

print(
    list(
        map(
            lambda element: (
                2 * element + 4
            ),
            l,
        )
    )
)
-4

because a lambda function is supposed to be one-lined, as its the simplest form of a function, an entrance, then return

4
  • 6
    No, anyone who writes an event-driven program will tell you that multiline lambda is important.
    – Xwtek
    Commented Feb 16, 2020 at 4:16
  • Is python an event-driven program? Commented Apr 16, 2021 at 8:27
  • So, you think just because it is written in Python, it means that the GUI has to be done completely imperatively?
    – Xwtek
    Commented Apr 18, 2021 at 3:37
  • You should handle it Pythonically rather than stacking lambdas. Commented May 3, 2021 at 6:12

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