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I've heard that the static_cast function should be preferred to C-style or simple function-style casting. Is this true? Why?

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    Objection your honour, asked and answered. Commented Sep 19, 2008 at 16:36
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    I disagree, this other question was about describing the differences between casts introduces in C++. This question is about the real usefulness of static_cast, which is slightly different. Commented Sep 19, 2008 at 16:40
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    We could certainly merge the two questions, but what we'd need to preserve from this thread is the advantage of using functions over C-style casting, which is currently only mentioned in a one-line answer in the other thread, with no votes. Commented Sep 20, 2008 at 8:26
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    This question is about "built-in" types, like int, whereas that question is about class types. That seems like a significant enough difference to merit a separate explanation.
    – user153275
    Commented Apr 19, 2011 at 21:21
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    static_cast is actually an operator, not a function. Commented Feb 25, 2013 at 13:47

9 Answers 9

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The main reason is that classic C casts make no distinction between what we call static_cast<>(), reinterpret_cast<>(), const_cast<>(), and dynamic_cast<>(). These four things are completely different.

A static_cast<>() is usually safe. There is a valid conversion in the language, or an appropriate constructor that makes it possible. The only time it's a bit risky is when you cast down to an inherited class; you must make sure that the object is actually the descendant that you claim it is, by means external to the language (like a flag in the object). A dynamic_cast<>() is safe as long as the result is checked (pointer) or a possible exception is taken into account (reference).

A reinterpret_cast<>() (or a const_cast<>()) on the other hand is always dangerous. You tell the compiler: "trust me: I know this doesn't look like a foo (this looks as if it isn't mutable), but it is".

The first problem is that it's almost impossible to tell which one will occur in a C-style cast without looking at large and disperse pieces of code and knowing all the rules.

Let's assume these:

class CDerivedClass : public CMyBase {...};
class CMyOtherStuff {...} ;

CMyBase  *pSomething; // filled somewhere

Now, these two are compiled the same way:

CDerivedClass *pMyObject;
pMyObject = static_cast<CDerivedClass*>(pSomething); // Safe; as long as we checked

pMyObject = (CDerivedClass*)(pSomething); // Same as static_cast<>
                                     // Safe; as long as we checked
                                     // but harder to read

However, let's see this almost identical code:

CMyOtherStuff *pOther;
pOther = static_cast<CMyOtherStuff*>(pSomething); // Compiler error: Can't convert

pOther = (CMyOtherStuff*)(pSomething);            // No compiler error.
                                                  // Same as reinterpret_cast<>
                                                  // and it's wrong!!!

As you can see, there is no easy way to distinguish between the two situations without knowing a lot about all the classes involved.

The second problem is that the C-style casts are too hard to locate. In complex expressions it can be very hard to see C-style casts. It is virtually impossible to write an automated tool that needs to locate C-style casts (for example a search tool) without a full blown C++ compiler front-end. On the other hand, it's easy to search for "static_cast<" or "reinterpret_cast<".

pOther = reinterpret_cast<CMyOtherStuff*>(pSomething);
      // No compiler error.
      // but the presence of a reinterpret_cast<> is 
      // like a Siren with Red Flashing Lights in your code.
      // The mere typing of it should cause you to feel VERY uncomfortable.

That means that, not only are C-style casts more dangerous, but it's a lot harder to find them all to make sure that they are correct.

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    You shouldn't use static_cast for casting down an inheritance hierarchy, but rather dynamic_cast. That will return either the null pointer or a valid pointer. Commented Jan 20, 2010 at 20:18
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    @David Thornley: I agree, usually. I think I indicated the caveats to using static_cast in that situation. dynamic_cast might be safer, but it's not always the best option. Sometimes you do know that a pointer points to a given subtype, by means opaque to the compiler, and a static_cast is faster. In at least some environments, dynamic_cast requires optional compiler support and runtime cost (enabling RTTI), and you might not want to enable it just for a couple of checks you can do yourself. C++'s RTTI is only one possible solution to the problem. Commented Jan 20, 2010 at 21:02
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    Your claim about C casts is false. All C casts are value conversions, roughly comparable to C++ static_cast. The C equivalent of reinterpret_cast is *(destination_type *)&, i.e. taking the address of the object, casting that address to a pointer to a different type, and then dereferencing. Except in the case of character types or certain struct types for which C defines the behavior of this construct, it generally results in undefined behavior in C. Commented Feb 4, 2012 at 5:56
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    Your fine answer addresses the body of the post. I was looking for an answer to the title "why use static_cast<int>(x) instead of (int)x". That is, for type int (and int alone), why use static_cast<int> vs. (int) as the only benefit seems to be with class variables and pointers. Request that you elaborate on this. Commented Dec 15, 2013 at 2:15
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    @chux, for int dynamic_cast doesn't apply, but all the other reasons stand. For example: let's say v is a function parameter declared as float, then (int)v is static_cast<int>(v). But if you change the parameter to float*, (int)v quietly becomes reinterpret_cast<int>(v) while static_cast<int>(v) is illegal and correctly caught by the compiler. Commented Dec 19, 2013 at 12:50
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One pragmatic tip: you can search easily for the static_cast keyword in your source code if you plan to tidy up the project.

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    you can search using the brackets also though such as "(int)" but good answer and valid reason to use C++ style casting.
    – Mike
    Commented Jan 7, 2014 at 11:28
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    @Mike that will find false positives - a function declaration with a single int parameter. Commented Sep 13, 2016 at 5:22
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    This can give false negatives: if you're searching a codebase where you're not the only author, you won't find C-style casts others might have introduced for some reasons.
    – Ruslan
    Commented Jun 9, 2017 at 6:46
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    How would doing this help to tidy up the project ?
    – Bilow
    Commented Oct 10, 2017 at 18:40
  • You would not search for static_cast, because it is most likely the correct one. You want to filter out static_cast, while you search for reinterpret_cast, const_cast, and maybe even dynamic_cast, as those would indicate places that can be redesigned. C-cast mixes in all together and doesn't give you the reason for casting.
    – Dragan
    Commented May 18, 2020 at 13:58
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In short:

  1. static_cast<>() gives you a compile time checking ability, C-Style cast doesn't.
  2. static_cast<>() can be spotted easily anywhere inside a C++ source code; in contrast, C_Style cast is harder to spot.
  3. Intentions are conveyed much better using C++ casts.

More Explanation:

The static cast performs conversions between compatible types. It is similar to the C-style cast, but is more restrictive. For example, the C-style cast would allow an integer pointer to point to a char.

char c = 10;       // 1 byte
int *p = (int*)&c; // 4 bytes

Since this results in a 4-byte pointer pointing to 1 byte of allocated memory, writing to this pointer will either cause a run-time error or will overwrite some adjacent memory.

*p = 5; // run-time error: stack corruption

In contrast to the C-style cast, the static cast will allow the compiler to check that the pointer and pointee data types are compatible, which allows the programmer to catch this incorrect pointer assignment during compilation.

int *q = static_cast<int*>(&c); // compile-time error

Read more on:
What is the difference between static_cast<> and C style casting
and
Regular cast vs. static_cast vs. dynamic_cast

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    I disagree that static_cast<>() is more readable. I mean, sometimes it is, but most of the time — especially on basic integer types — it's just horribly and unnecessarily verbose. For example: This is a function that swaps the bytes of a 32-bit word. It would be nearly impossible to read using static_cast<uint##>() casts, but is quite easy to understand using (uint##) casts. Picture of code: imgur.com/NoHbGve Commented Aug 4, 2015 at 22:17
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    @ToddLehman: Thank you, but I didnt say always either. (but most of the times yes) There sure are cases where the c style cast is way more readable. Thats one of the reasons c style casting is still live and kicking in c++ imho. :) By the way that was a very nice example
    – Hossein
    Commented May 23, 2016 at 10:06
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    @ToddLehman code in that image uses two casts chained ((uint32_t)(uint8_t)) to achieve that bytes besides lowest are reset. For that there is bitwise and (0xFF &). Usage of casts is obfuscating the intention.
    – Öö Tiib
    Commented Aug 20, 2018 at 13:02
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    static_cast<int> is not unreadable, it's just verbose. It is also unambiguous, in terms of the compile-time behavior. The argument for readability over clarity can only win by convincing us that the reader will find more bugs in ambiguous-but-readable code than a compiler will find when it is compiling semantically unambiguous code. It cannot be won just by claiming that "this is more readable than that" -- but if that were indeed the only point of debate, I think static_cast<int> is in the lead, particularly since unambiguity is itself a property of readability. Commented Dec 27, 2021 at 19:42
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    @ToddLehman Your code is an exact example of why to avoid casts in the first place. (see alternative implementation without casts fxr.watson.org/fxr/source/lib/libkern/bswap32.c?v=NETBSD3)
    – j123b567
    Commented Mar 16, 2022 at 10:45
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The question is bigger than just using whether static_cast<> or C-style casting because there are different things that happen when using C-style casts. The C++ casting operators are intended to make those different operations more explicit.

On the surface static_cast<> and C-style casts appear to be the same thing, for example when casting one value to another:

int i;
double d = (double)i;                  //C-style cast
double d2 = static_cast<double>( i );  //C++ cast

Both of those cast the integer value to a double. However when working with pointers things get more complicated. Some examples:

class A {};
class B : public A {};

A* a = new B;
B* b = (B*)a;                                  //(1) what is this supposed to do?

char* c = (char*)new int( 5 );                 //(2) that weird?
char* c1 = static_cast<char*>( new int( 5 ) ); //(3) compile time error

In this example (1) may be OK because the object pointed to by A is really an instance of B. But what if you don't know at that point in code what a actually points to?

(2) may be perfectly legal (you only want to look at one byte of the integer), but it could also be a mistake in which case an error would be nice, like (3).

The C++ casting operators are intended to expose these issues in the code by providing compile-time or run-time errors when possible.

So, for strict "value casting" you can use static_cast<>. If you want run-time polymorphic casting of pointers use dynamic_cast<>. If you really want to forget about types, you can use reintrepret_cast<>. And to just throw const out the window there is const_cast<>.

They just make the code more explicit so that it looks like you know what you were doing.

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static_cast means that you can't accidentally const_cast or reinterpret_cast, which is a good thing.

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    Additional (though rather minor) advantages over the C style cast is that it stands out more (doing something potentially bad should look ugly) and it's more grep-able. Commented Sep 19, 2008 at 16:52
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    grep-ability is always a plus, in my book.
    – Branan
    Commented Sep 22, 2008 at 19:15
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  1. Allows casts to be found easily in your code using grep or similar tools.
  2. Makes it explicit what kind of cast you are doing, and engaging the compiler's help in enforcing it. If you only want to cast away const-ness, then you can use const_cast, which will not allow you to do other types of conversions.
  3. Casts are inherently ugly -- you as a programmer are overruling how the compiler would ordinarily treat your code. You are saying to the compiler, "I know better than you." That being the case, it makes sense that performing a cast should be a moderately painful thing to do, and that they should stick out in your code, since they are a likely source of problems.

See Effective C++ Introduction

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  • I completely agree with this for classes but does using C++ style cast's for POD types make any sense? Commented Aug 27, 2014 at 21:44
  • I think so. All 3 reasons apply to PODs, and it's helpful to have just one rule, rather than separate ones for classes and PODs.
    – JohnMcG
    Commented Sep 12, 2014 at 19:12
  • Interesting, I might have to modify how I do my casts in future code for POD types. Commented Sep 14, 2014 at 3:35
  • I disagree..often we just have to cast. E.g. we are stuck with std::container.size() returning unsigned. Generally using unsigneds for index type isn't appropriate. So comparing against size() needs a rather trivial cast. That cast shouldn't be painful, because if it's becoming too painful, we're going to just turn off respective warnings Commented Mar 5 at 15:42
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C Style casts are easy to miss in a block of code. C++ style casts are not only better practice; they offer a much greater degree of flexibility.

reinterpret_cast allows integral to pointer type conversions, however can be unsafe if misused.

static_cast offers good conversion for numeric types e.g. from as enums to ints or ints to floats or any data types you are confident of type. It does not perform any run time checks.

dynamic_cast on the other hand will perform these checks flagging any ambiguous assignments or conversions. It only works on pointers and references and incurs an overhead.

There are a couple of others but these are the main ones you will come across.

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It's about how much type-safety you want to impose.

When you write (bar) foo (which is equivalent to reinterpret_cast<bar> foo if you haven't provided a type conversion operator) you are telling the compiler to ignore type safety, and just do as it's told.

When you write static_cast<bar> foo you are asking the compiler to at least check that the type conversion makes sense and, for integral types, to insert some conversion code.


EDIT 2014-02-26

I wrote this answer more than 5 years ago, and I got it wrong. (See comments.) But it still gets upvotes!

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    (bar)foo is not equivalent to reinterpret_cast<bar>(foo). The rules for "(TYPE) expr" are that it will choose the appropriate C++ style cast to use, which may include reinterpret_cast. Commented Sep 19, 2008 at 17:43
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    Good point. Euro Micelli gave the definitive answer for this question.
    – Pitarou
    Commented Sep 20, 2008 at 17:03
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    Also, it is static_cast<bar>(foo), with parentheses. Same for reinterpret_cast<bar>(foo).
    – L. F.
    Commented Jul 25, 2019 at 1:58
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static_cast, aside from manipulating pointers to classes, can also be used to perform conversions explicitly defined in classes, as well as to perform standard conversions between fundamental types:

double d = 3.14159265;
int    i = static_cast<int>(d);
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    Why would anyone write static_cast<int>(d), though, when (int)d is so much more concise and readable? (I mean in the case of basic types, not object pointers.) Commented Aug 4, 2015 at 22:21
  • @gd1 — Why would anyone put consistency above readability? (actually half serious) Commented Jan 13, 2016 at 19:35
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    @ToddLehman : Me, considering that making an exception for certain types just because they're somehow special to you does not make any sense to me, and I also disagree on your very notion of readability. Shorter does not mean more readable, as I see from the image you posted in another comment.
    – gd1
    Commented Jan 13, 2016 at 19:45
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    static_cast is a clear and conscious decision to make a very particular kind of conversion. It therefore adds to clarity of intention. It's also very handy as a marker to search source files for conversions in a code review, bug or upgrading exercise.
    – Persixty
    Commented Jan 18, 2016 at 10:19
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    @ToddLehman counterpoint: Why would anyone write (int)d when int{d} is so much more readable? Constructor, or function-like if you have (), syntax isn't nearly so fast to devolve into a nightmarish maze of parentheses in complex expressions. In this case, it'd be int i{d} instead of int i = (int)d. Far better IMO. That said, when I just need a temporary in an expression, I use static_cast and have never used constructor casts, I don't think. I only use (C)casts when hurriedly writing debug couts... Commented May 12, 2017 at 23:39

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