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edited Mar 7, 2020 at 16:08

This is confusing me.

false || echo "Oops, fail" # Oops, fail
true || echo "Will not be printed" #
true && echo "Things went well" # Things went well
false && echo "Will not be printed" #

true return 0 exit code and false returns 1. I am unable to understand how || and && are working. Do both of them work on exit codes or the actual output of the command? What is the difference between && and || operator here?

The above code snippet is from the missing semester of your CS education lecture 2.

This is confusing me.

false || echo "Oops, fail" # Oops, fail
true || echo "Will not be printed" #
true && echo "Things went well" # Things went well
false && echo "Will not be printed" #

true return 0 exit code and false returns 1. I am unable to understand how || and && are working. Do both of them work on exit codes or the actual output of the command?

The above code snippet is from the missing semester of your CS education lecture 2.

This is confusing me.

false || echo "Oops, fail" # Oops, fail
true || echo "Will not be printed" #
true && echo "Things went well" # Things went well
false && echo "Will not be printed" #

The above code snippet is from the missing semester of your CS education lecture 2.

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asked Mar 7, 2020 at 15:07

Mubashir Ali

Difference between && and || operator in Bash

This is confusing me.

false || echo "Oops, fail" # Oops, fail
true || echo "Will not be printed" #
true && echo "Things went well" # Things went well
false && echo "Will not be printed" #

true return 0 exit code and false returns 1. I am unable to understand how || and && are working. Do both of them work on exit codes or the actual output of the command?

The above code snippet is from the missing semester of your CS education lecture 2.

bash

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Difference between && and || operator in Bash