Revisions to How do you JSON.stringify an ES6 Map?

added 1 character in body

Source Link

edited Nov 26, 2019 at 13:02

Using spread sytax Map can be serialized in one line:

JSON.stringify([...new Map()]);

and deserialize it with:

let map = new Map(JSON.parse(map));

Using spread sytax Map can be serialized in one line:

JSON.stringify([...new Map()]);

and deserialize it with:

let map = new Map(JSON.parse(map))

Using spread sytax Map can be serialized in one line:

JSON.stringify([...new Map()]);

and deserialize it with:

let map = new Map(JSON.parse(map));

Rollback to Revision 1

Source Link

edited Nov 25, 2019 at 12:42

Using spread sytax Map can be serialized in one line:

JSON.stringify([...new Map()]);

and deserialize it with:

let map = new Map(JSON.parse(map))

Using spread sytax Map can be serialized in one line:

JSON.stringify([...new Map()]);

and deserialize it with:

let map = new Map(JSON.parse(map))

Using spread sytax Map can be serialized in one line:

JSON.stringify([...new Map()]);

and deserialize it with:

let map = new Map(JSON.parse(map))

deleted 65 characters in body

Source Link

edited Nov 25, 2019 at 12:40

Using spread sytax Map can be serialized in one line:

JSON.stringify([...new Map()]);

and deserialize it with:

let map = new Map(JSON.parse(map))

output format:

  // [["key1","value1"],["key2","value2"]]

Using spread sytax Map can be serialized in one line:

JSON.stringify([...new Map()]);

and deserialize it with:

let map = new Map(JSON.parse(map))

output format:

  // [["key1","value1"],["key2","value2"]]

Using spread sytax Map can be serialized in one line:

JSON.stringify([...new Map()]);

and deserialize it with:

let map = new Map(JSON.parse(map))

added 70 characters in body

Source Link

edited Nov 25, 2019 at 12:00

Loading

Source Link

created Oct 30, 2019 at 12:54

Loading

Return to Answer