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Rishabh Anand
Rishabh Anand
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If youThere are using JavaScript on a website(i.e; or any front2 answers forthis for two different senarios:-end part) The simplest way

  1. If you are using JavaScript on a website(i.e; or any front-end part) The simplest way to do it is:

     <h2>The Navigator Object</h2>

 <p>The onLine property returns true if the browser is online:</p>

 <p id="demo"></p>

 <script>
   document.getElementById("demo").innerHTML = "navigator.onLine is " + navigator.onLine;
 </script>

  2. But if you're using js on server side(i.e; node etc.), You can determine that the connection is lost by making failed XHR requests.

The standard approach is to doretry the request a few times. If it is:doesn't go through, alert the user to check the connection, and fail gracefully.

<!DOCTYPE html>
<html>
  <body>

    <h2>The Navigator Object</h2>

    <p>The onLine property returns true if the browser is online:</p>

    <p id="demo"></p>

    <script>
      document.getElementById("demo").innerHTML = "navigator.onLine is " + navigator.onLine;
    </script>

  </body>
</html>

If you are using JavaScript on a website(i.e; or any front-end part) The simplest way to do it is:

<!DOCTYPE html>
<html>
  <body>

    <h2>The Navigator Object</h2>

    <p>The onLine property returns true if the browser is online:</p>

    <p id="demo"></p>

    <script>
      document.getElementById("demo").innerHTML = "navigator.onLine is " + navigator.onLine;
    </script>

  </body>
</html>

There are 2 answers forthis for two different senarios:-

  1. If you are using JavaScript on a website(i.e; or any front-end part) The simplest way to do it is:

     <h2>The Navigator Object</h2>

 <p>The onLine property returns true if the browser is online:</p>

 <p id="demo"></p>

 <script>
   document.getElementById("demo").innerHTML = "navigator.onLine is " + navigator.onLine;
 </script>

  2. But if you're using js on server side(i.e; node etc.), You can determine that the connection is lost by making failed XHR requests.

The standard approach is to retry the request a few times. If it doesn't go through, alert the user to check the connection, and fail gracefully.

added 73 characters in body
Source Link
Rishabh Anand
Rishabh Anand
  • 167
  • 3
  • 12

TheIf you are using JavaScript on a website(i.e; or any front-end part) The simplest way to do it is:

<!DOCTYPE html>
<html>
  <body>

    <h2>The Navigator Object</h2>

    <p>The onLine property returns true if the browser is online:</p>

    <p id="demo"></p>

    <script>
      document.getElementById("demo").innerHTML = "navigator.onLine is " + navigator.onLine;
    </script>

  </body>
</html>

The simplest way to do it is:

<!DOCTYPE html>
<html>
  <body>

    <h2>The Navigator Object</h2>

    <p>The onLine property returns true if the browser is online:</p>

    <p id="demo"></p>

    <script>
      document.getElementById("demo").innerHTML = "navigator.onLine is " + navigator.onLine;
    </script>

  </body>
</html>

If you are using JavaScript on a website(i.e; or any front-end part) The simplest way to do it is:

<!DOCTYPE html>
<html>
  <body>

    <h2>The Navigator Object</h2>

    <p>The onLine property returns true if the browser is online:</p>

    <p id="demo"></p>

    <script>
      document.getElementById("demo").innerHTML = "navigator.onLine is " + navigator.onLine;
    </script>

  </body>
</html>
Source Link
Rishabh Anand
Rishabh Anand
  • 167
  • 3
  • 12

The simplest way to do it is:

<!DOCTYPE html>
<html>
  <body>

    <h2>The Navigator Object</h2>

    <p>The onLine property returns true if the browser is online:</p>

    <p id="demo"></p>

    <script>
      document.getElementById("demo").innerHTML = "navigator.onLine is " + navigator.onLine;
    </script>

  </body>
</html>