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Rev

So the result is decimal or double that will never have anything after the point but there is not built in object to store the result as an "int" (without decimal places) that seems a bit lame?
– Paul C
Commented May 11, 2014 at 21:48
@CodeBlend: There isn't much call for designing frameworks around a desire to lose precision.
– user1228
Commented May 12, 2014 at 13:01
@CodeBlend: You would still lose precision because you are chopping off the decimal values of a number. Not sure what you're getting at.
– user1228
Commented May 12, 2014 at 15:02
Not sure this will work or not. Because Math.Truncate(-5.99999999999999999) returns -6.0 for me...!!
– Bharat Mori
Commented Oct 19, 2017 at 18:56
@Bharat Mori: It seems that -5.99999999999999999 is rounded to -6.0 before the truncate. Try with the suffix "m" and it'll work. Math.Truncate(-5.99999999999999999m) gives -5.
– Henry
Commented Feb 23, 2018 at 10:30

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create code fences with backticks ` or tildes ~
```
like so
```
add language identifier to highlight code
```python
def function(foo):
print(foo)
```
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indent code by 4 spaces
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quote by placing > at start of line
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