Timeline for How can I declare and use Boolean variables in a shell script?
Current License: CC BY-SA 4.0
11 events
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| May 19, 2023 at 16:11 | comment | added | Max Cascone |
This is obviously (to me) the most clear syntax, but there's gotta be a catch somewhere. I don't think it works with integer values: > bucket_available=0; > if ($bucket_available); then echo hi; fi bash: 0: command not found
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| Oct 24, 2019 at 6:31 | history | edited | will | CC BY-SA 4.0 |
Return conjunction to English punctuation
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| Oct 23, 2019 at 12:14 | history | edited | Peter Mortensen | CC BY-SA 4.0 |
Made compliant with the Jon Skeet Decree - <https://twitter.com/PeterMortensen/status/976400000942034944>.
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| S Feb 2, 2018 at 7:08 | history | edited | will | CC BY-SA 3.0 |
structure edited + removed unnecessary text = overall better for readers now
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| S Feb 2, 2018 at 7:08 | history | suggested | Vlastimil Burián | CC BY-SA 3.0 |
structure edited + removed unnecessary text = overall better for readers now
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| Feb 2, 2018 at 6:10 | review | Suggested edits | |||
| S Feb 2, 2018 at 7:08 | |||||
| Nov 6, 2017 at 7:13 | comment | added | will |
@Blauhirn ... Hi, I based my comments on experiments with GNU Bash on a Linux Mint /Ubuntu PC. You are probably right in theory ()-s are not needed. My only response, is try it out, it seems to depend on Bash version, the actual expression or context and such.
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| Nov 3, 2017 at 17:00 | comment | added | phil294 | @will yes it does. You dont need the ()s. | |
| Mar 6, 2016 at 11:01 | comment | added | will | Without parentheses the expression doesn't evaluate. | |
| Mar 4, 2016 at 13:56 | comment | added | dolmen | Where you remove the parentheses, this is exactly @miku's original answer at the top. | |
| Sep 22, 2015 at 1:21 | history | answered | will | CC BY-SA 3.0 |