No offense folks, but for such a simple problem, you are making things way too complicated. There are a lot of reasons to use Boost. But for something this simple, it's like hitting a fly with a 20# sledge.
void
split( vector<string> & theStringVector, /* Altered/returned value */
const string & theString,
const string & theDelimiter)
{
UASSERT( theDelimiter.size(), >, 0); // My own ASSERT macro.
size_t start = 0, end = 0;
while ( end != string::npos)
{
end = theString.find( theDelimiter, start);
// If at end, use length=maxLength. Else use length=end-start.
theStringVector.push_back( theString.substr( start,
(end == string::npos) ? string::npos : end - start));
// If at end, use start=maxSize. Else use start=end+delimiter.
start = ( ( end > (string::npos - theDelimiter.size()) )
? string::npos : end + theDelimiter.size());
}
}
For example (for Doug's case),
#define SHOW(I,X) cout << "[" << (I) << "]\t " # X " = \"" << (X) << "\"" << endl
int
main()
{
vector<string> v;
split( v, "A:PEP:909:Inventory Item", ":" );
for (unsigned int i = 0; i < v.size(); i++)
SHOW( i, v[i] );
}
And yes, we could have split() return a new vector rather than passing one in. It's trivial to wrap and overload. But depending on what I'm doing, I often find it better to re-use pre-existing objects rather than always creating new ones. (Just as long as I don't forget to empty the vector in between!)
Reference: http://www.cplusplus.com/reference/string/string/.
(I was originally writing a response to Doug's question: C++ Strings Modifying and Extracting based on Separators (closed)C++ Strings Modifying and Extracting based on Separators (closed). But since Martin York closed that question with a pointer over here... I'll just generalize my code.)