Timeline for How to split one iterator into two?

9 events

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Jun 15, 2015 at 23:25	comment	added	lqdc		That would generate `n` tries for `n` items in the iterable. Basically I want one object at the end, and you cannot pass another iterable to it once it's finished with the first one.
Jun 15, 2015 at 23:23	comment	added	Ricardo Cárdenes		I think the only important part there is if `marisa_trie.Trie(iterable)` returns the same as `[marisa_trie.Trie([x]) for x in iterable]`. Then you can call `a` and `b` separately for each key, and this works.
Jun 15, 2015 at 23:18	comment	added	lqdc		alright, replace `a` with `def a(iterable): return marisa_trie.Trie(iterable)`. So I was wrong when saying they are stateless. They expect the whole iterable to generate output and then it's read only after that. An example is from this package: github.com/kmike/marisa-trie
Jun 15, 2015 at 23:14	comment	added	Ricardo Cárdenes		Well, if the functions are really stateless, then I don't see how this shouldn't work. Either that, or there's still something we need to learn about your problem
Jun 15, 2015 at 23:12	comment	added	lqdc		well, they need the whole iterator to generate output. Like you cannot add to a trie once it's generated because it's read only after that.
Jun 15, 2015 at 23:10	history	undeleted	Ricardo Cárdenes
Jun 15, 2015 at 23:10	history	edited	Ricardo Cárdenes	CC BY-SA 3.0	Even better
Jun 15, 2015 at 22:44	history	deleted	Ricardo Cárdenes		via Vote
Jun 15, 2015 at 22:44	history	answered	Ricardo Cárdenes	CC BY-SA 3.0